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mart [117]
3 years ago
13

The gravitational force of a star on an orbiting planet 1 is F1. Planet 2, which is twice as massive as planet 1 and orbits at t

hree times larger distance from the star, experiences gravitational force F2.
What is the ratio F2F1? You can ignore the gravitational force between the two planets.
Physics
1 answer:
Andrej [43]3 years ago
8 0

Answer:

ratio = 1 : 4.5

Explanation:

If m₁ is the mass of the star and m₂ the mass of the planet, the force of gravity F₁ for planet 1 is given by:

F_1=\frac{Gm_1m_2}{r^2}

The force F₂:

F_2=\frac{Gm_1(2m_2)}{(3r)^2}

The ratio:

\frac{F_2}{F_1}=\frac{2}{9}

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Given speed and the distance that must be covered, the time it will take the ultraviolet light to reach the earth is 3.7 × 10⁴ hours.

<h3>What is Speed?</h3>

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

  • Speed of the Ultraviolet light c = 3.0 × 10⁸m/s = 1.08 × 10⁹km/h
  • Distance it must cover d = 4.0 × 10¹³km
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We substitute our given values into the expression above.

Speed = Distance ÷ time

1.08 × 10⁹km/h = 4.0 × 10¹³km ÷ t

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t = 3.7 × 10⁴ hrs

Therefore, given speed and the distance that must be covered, the time it will take the ultraviolet light to reach the earth is 3.7 × 10⁴ hours.

Learn more about speed here: brainly.com/question/7359669

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A paleontologist measures the ratio of carbon-14 to carbon-12 in a fossil skull found at a site. What technique is he using and
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A small airplane has to reach a speed if 27.8 m/s to takeoff. It can accelerate at 2.00 m/s^2. What is the minimal length of run
pickupchik [31]
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3 0
3 years ago
A book, that has a mass of 0.5 grams, is pushed across a table with a force of 20 newtons. What is the acceleration of the book?
Bas_tet [7]

Answer:

4\cdot 10^4 m/s^2

Explanation:

The acceleration of an object is given by Newton's second law:

a=\frac{F}{m}

where

F is the net force applied on the object

m is the mass of the object

For the book in the problem, we have:

m=0.5 g =5\cdot 10^{-4} kg is the mass

F=20 N is the force applied

Substituting into the formula, we find the acceleration:

a=\frac{20 N}{5\cdot 10^{-4} kg}=4\cdot 10^4 m/s^2

6 0
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