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Ber [7]
2 years ago
6

-09utydrbfshjkloiuohyfdgxfncj

Physics
1 answer:
adoni [48]2 years ago
5 0

Answer:

thanks

Explanation:

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In an electric field, 0.90 joule of work is required to bring 0.45 coulomb of charge from point a to point
jarptica [38.1K]
The difference in electric potential energy between the two points is
\Delta U = q \Delta V
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But for energy conservation, the difference in electric potential energy \Delta U between the two points is equal to the work done to move the charge between A and B:
W=\Delta U
so we have
W=q \Delta V

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\Delta V =  \frac{W}{q}= \frac{0.90 J}{0.45 C}=2 V
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3 years ago
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Jlenok [28]
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3 years ago
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1<span>Define the equation for the force of gravity that attracts an object, <span>Fgrav = (Gm1m2)/d2</span>
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