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Anastasy [175]
2 years ago
15

A constant eastward horizontal force of 70 N is applied to a 12 kg crate

Physics
1 answer:
Bingel [31]2 years ago
8 0

Answer:

Explanation:

If you are looking for acceleration, then F = ma, where F is the force, m is the mass, and a is acceleration. The direction is eastward and we will call that positive. Therefore,

70.0 = 12a and

a = 5.8 m/s/s

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here

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A. the indices of refraction matched

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A 0.05-kg car starts from rest at a height of 0.95 m. Assuming no friction, what is the kinetic energy of the car when it reache
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The kinetic energy of the car is A.) 0.466 J
6 0
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what is the name of the tool that allows you to copy two or more shapes into a single part? when working with 3D
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8 0
3 years ago
The magnetic flux through each turn of a 110-turn coil is given by ΦB = 9.75 ✕ 10−3 sin(ωt), where ω is the angular speed of the
Xelga [282]

Answer:

Explanation:

Given that a coil has a turns of

N = 110 turns

And the flux is given as function of t

ΦB = 9.75 ✕ 10^-3 sin(ωt),

Given that, at an instant the angular velocity is 8.70 ✕ 10² rev/min

ω = 8.70 ✕ 10² rev/min

Converting this to rad/sec

1 rev = 2πrad

Then,

ω = 8.7 × 10² × 2π / 60

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Now, we want to find the induced EMF as a function of time

EMF is given as

ε = —NdΦB/dt

ΦB = 9.75 ✕ 10^-3 sin(ωt),

dΦB/dt = 9.75 × 10^-3•ω Cos(ωt)

So,

ε = —NdΦB/dt

ε = —110 × 9.75 × 10^-3•ω Cos(ωt)

Since ω = 91.11 rad/s

ε = —110 × 9.75 × 10^-3 ×91.11 Cos(91.11t)

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The EMF as a function of time is

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Extra

The maximum EMF will be when Cos(91.11t) = -1

Then, maximum emf = 97.71V

8 0
3 years ago
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