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kirza4 [7]
3 years ago
5

What is relationship between latent heat and water ?

Physics
1 answer:
Wittaler [7]3 years ago
5 0
Latent heat, energy absorbed or released by a substance during a change in its physical state (phase) that occurs without changing its temperature.
You might be interested in
What did Blaise Pascal discover, and how did he impact Physics?
yan [13]

Answer:

Well it really depends because he found out about a lot of things in a lot of scientific fields actually. He is known for contributing Pascal's triangle and probability theory. He also invented an early digital calculator and a roulette machine. In the field of physics, Blaise contributed to the study of atmospheric pressure by discovering that vacuums are real and exist in the real world.

6 0
3 years ago
A 7 kg suitcase and a 12 kg suitcase are dropped from the same second story window at the same time. If there is no wind resista
Natali5045456 [20]

Explanation:

the correct answer is C.

if there is no wind resistance; in vaccum both will hit the ground at the same time.

hope this helps you and if possible please mark me as BRAINLIST.

4 0
2 years ago
5 kilo meters = ___________meters
DiKsa [7]

Answer:

5,000 meters

Explanation:

4 0
3 years ago
Assume that the average mass of each of the approximately 1 billion people in China is 55 kg.Assume that they all gather in one
Harman [31]

Answer: 5.9(10)^{-8} m

Explanation:

The equation to calculate the center of mass C_{M} of a particle system is:

C_{M}=\frac{m_{1}r_{1}+m_{1}r_{1}+...+m_{n}r_{n}}{m_{1}+m_{2}+...+m_{n}}

In this case we can arrange for one dimension, assuming the geometric center of the Earth and the ladder are on a line, and assuming original center of mass located at the Earth's geometric center:

C_{M}=\frac{m_{E}(0 m) + m_{p} r_{E-p}}{m_{E}+m_{p}}

Where:

m_{E}=5.9(10)^{24} kg is the mass of the Earth

m_{p}=55(10)^{9} kg is the mass of 1 billion people

r_{E}=6371000 m is the radius of the Earth

r_{E-p}=6371000 m- 2m=6370998 m is the distance between the center of the Earth and the position of the people (2 m above the Earth's surface)

C_{M}=\frac{m_{p}55(10)^{9} kg (6370998 m)}{5.9(10)^{24} kg+55(10)^{9} kg}

C_{M}=5.9(10)^{-8} m This is the displacement of Earth's center of mass from the original center.

8 0
3 years ago
The 1.5kg ball is launched straight upward with an initial velocity of 7m/s. What is the maximum height it will reach?​
Temka [501]

Answer:

h = 2.5 m

Explanation:

Given that,

Mass of a ball, m = 1.5 kg

Initial velocity of the ball, u = 7 m/s

We need to find the maximum height reached by the ball. Let it is be h. Using the conservation of energy to find it such that,

mgh=\dfrac{1}{2}mu^2\\\\h=\dfrac{u^2}{2g}

Put all the values,

h=\dfrac{7^2}{2\times 9.8}\\\\=2.5\ m

So, it will reach to a height of 2.5 m.

8 0
3 years ago
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