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bekas [8.4K]
2 years ago
6

You need to make 10.0 L of 1.2 M KNO3. What molar ( concentration) would the potassium nitrate solution need to be if you were t

o use only 2.5 L of it? *​
Chemistry
1 answer:
solniwko [45]2 years ago
6 0

Answer:

2.5L [NaCl] concentrate needs to be 4.8 Molar solution before dilution to prep 10L of 1.2M KNO₃ solution.

Explanation:

Generally, moles of solute in solution before dilution must equal moles of solute after dilution.

By definition Molarity = moles solute/volume of solution in Liters

=> moles solute = Molarity x Volume (L)

Apply moles before dilution = moles after dilution ...

=> (Molarity X Volume)before dilution = (Molarity X Volume)after dilution

=> (M)(2.5L)before = (1.2M)(10.0L)after

=> Molarity of 2.5L concentrate = (1.2M)(10.0L)/(2.5L) = 4.8 Molar concentrate

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A helium balloon at 23 C has a volume of 755 mL. The balloon is placed into a freezer kept at -10 C. Assuming pressure is consta
Vera_Pavlovna [14]

Explanation:

T1/V1 = T2/V2

V2 = T2 x V1/T1

V2 = 296.15x535/319.15

V2 = 496.44mL

5 0
3 years ago
What is the energy of an electromagnetic wave with a frequency of 8 x 10^12
omeli [17]

Answer:

Energy, E=5.3\times 10^{-21}\ J

Explanation:

It is required to find the energy of an electromagnetic wave with a frequency of 8\times 10^{12}\ Hz. The energy of a wave in terms of its frequency is given by :

E=h\nu

\nu = frequency of em wave

E=6.63\times 10^{-34}\times 8\times 10^{12}\\\\E=5.3\times 10^{-21}\ J

So, the energy of an electromagnetic wave is 5.3\times 10^{-21}\ J

4 0
3 years ago
Calculate the concentration of formate in a 100mm solution of formic acid at ph 4.15. The pka for formic acid is 3.75
MissTica

The molarity of formic acid is 100 mM or 100\times 10^{-3}M. The dissociation reaction of formic acid is as follows:

HCOOH\leftrightharpoons HCOO^{-}+H^{+}

The expression for dissociation constant of the reaction will be:

K_{a}=\frac{[HCOO^{-}][H^{+}]}{[HCOOH]}

Rearranging,

[HCOO^{-}]=\frac{K_{a}[HCOOH]}{[H^{+}]}

Here, pH of solution is 4.15 thus, concentration of hydrogen ion will be:

[H^{+}]=10^{-pH}=10^{-4.15}=7.08\times 10^{-5}M

Similarly, pK_{a}=3.75 thus,

[K_{a}=10^{-pK_{a}}=10^{-3.75}=1.78\times 10^{-4}M

Putting the values,

[HCOO^{-}]=\frac{(1.78\times 10^{-4}M)(100\times 10^{-3}M)}{(7.08\times 10^{-5}M}=0.2511 M

Therefore, the concentration of formate will be 0.2511 M.

4 0
3 years ago
1. How many molecules are found in 13.7 moles of CuNO3? <br><br> Please explain step by step
Gennadij [26K]

Answer:

1 moles

Explanation:

The answer is 0.0011897028836018. We assume you are converting between moles CuNo3 and gram. You can view more details on each measurement unit: molecular weight of CuNo3 or grams The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CuNo3, or 840.546 grams.

7 0
3 years ago
Solid cadmium sulfide reacts with an aqueous solution of sulfuric acid . Express your answer as a balanced chemical equation. Id
max2010maxim [7]

Explanation:

When solid cadmium sulfide reacts with an aqueous solution of sulfuric acid then the reaction will be as follows.

          CdS(s) + H_{2}SO_{4}(aq) \rightarrow CdSO_{4}(aq) + H_{2}S(g)

Hence, ionic equation for this reaction is as follows.

      CdS(s) + 2H^{+}(aq) + SO^{2-}_{4}(aq) \rightarrow Cd^{2+}(aq) + SO^{2-}_{4}(aq) + H_{2}S(g)

Therefore, net ionic equation for this reaction is as follows.

      CdS(s) + 2H^{+}(aq) \rightarrow Cd^{2+}(aq) + H_{2}S(g)

8 0
3 years ago
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