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Inessa [10]
3 years ago
15

Gravitational potential energy is often released by burning substances. true or false

Physics
2 answers:
juin [17]3 years ago
6 0
False because gravitational potential energy has to do with gravity
jolli1 [7]3 years ago
4 0
Gravitational potential energy is caused when an object is resting above the ground. It is released when the object is falling, not by burning substances.
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How much work can a 22kw car engine do in 60 seconds
Sindrei [870]

Answer:

13.2 x 10^5 J

Explanation:

Power = work/time

Given

Power = 22kw

= 22 x 1000 = 22000w

Time = 60 secs

Therefore

22000 = work/60

Cross multiply

Work = 22000 x 60

= 1320000

= 13.2 x 10^5J

6 0
3 years ago
Read 2 more answers
Instrumento que se utiliza para medir fuerzas
Klio2033 [76]

Answer:

Un medidor de fuerza

A force gauge for all you English speakers

Explanation:

Un medidor de fuerza es un instrumento de medición que se utiliza para medir fuerzas.

A force gauge is a measuring instrument used to measure forces.

8 0
3 years ago
A Hooke's law spring is mounted horizontally over a frictionless surface. The spring is then compressed a distance d and is used
zloy xaker [14]

Answer:

The compression is \sqrt{2} \  d.

Explanation:

A Hooke's law spring compressed has a potential energy

E_{potential} = \frac{1}{2} k (\Delta x)^2

where k is the spring constant and \Delta x the distance to the equilibrium position.

A mass m moving at speed v has a kinetic energy

E_{kinetic} = \frac{1}{2} m v^2.

So, in the first part of the problem, the spring is compressed a distance d, and then launch the mass at velocity v_1. Knowing that the energy is constant.

\frac{1}{2} m v_1^2 = \frac{1}{2} k d^2

If we want to double the kinetic energy, then, the knew kinetic energy for a obtained by compressing the spring a distance D, implies:

2 * (\frac{1}{2} m v_1^2) = \frac{1}{2} k D^2

But, in the left side we can use the previous equation to obtain:

2 * (\frac{1}{2} k d^2) = \frac{1}{2} k D^2

D^2 =  \frac{2 \ (\frac{1}{2} k d^2)}{\frac{1}{2} k}

D^2 =  2 \  d^2

D =  \sqrt{2 \  d^2}

D =  \sqrt{2} \  d

And this is the compression we are looking for

3 0
4 years ago
Read 2 more answers
the (speed) of an object is a vector quantity that tells us the speed and direction of an objects momentum is this correct? If n
Ivenika [448]

Answer:

sorry kailangan points wh

7 0
3 years ago
Read 2 more answers
The vertical velocity of a projectile launch at 35 degree : O continuously decreases O continuously increases O sometimes decrea
kati45 [8]

Answer:Sometime decreases and sometime increases.

Explanation:

Given

Projectile is launched at 35 ^{\circ}

so horizontal velocity=ucos35

vertical velocity=usin35

since gravity acts in the vertical direction, therefore, it affects only the vertical component of the projectile.

So Vertical velocity first decrease up to maximum height and then starts to increase.

7 0
3 years ago
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