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GuDViN [60]
2 years ago
8

Q1- Classify each of the molecules given below by molecular geometry.

Chemistry
1 answer:
Ludmilka [50]2 years ago
3 0
It would be carbon dioxide codd2 for the molecules
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Why is platinum metal preferred to other metals for the flame test​
Mama L [17]

Answer:

Platinum is especially good for this because it is unreactive, and does not produce a color in the flame which will mask the presence of other metals.

Hope this answer is right!

8 0
3 years ago
Read 2 more answers
How many grams of N2 are in 3.0 x 1023 molecules of N2?
Oduvanchick [21]

The mass of 3.0 x 10²³ molecules of nitrogen gas is 13.95 g.

<h3>Mass of the Nitrogen gas</h3>

The mass of one mole of Nitrogen gas is 28 g/mol.

<h3>Number of atoms </h3>

The number of atoms in one mole of Nitrogen gas is 6.022 x 10²³ molecules.

The mass of Nitrogen gas in the given number of molecules is calculated as follows;

6.022 x 10²³  --------------------- 28 g/mol

3.0 x 10²³ ----------------------------- ?

= \frac{3.0 \times 10^{23} \times 28}{6.022 \times 10^{23} } \\\\= 13.95 \ g

Thus, the mass of 3.0 x 10²³ molecules of nitrogen gas is 13.95 g.

Learn more about mass of gas molecules here: brainly.com/question/11641158

6 0
3 years ago
C3H2 + 502 + 3 CO2 + 4H20
nordsb [41]

Answer: 6.2 moles

Explanation:

C3H8(g) + 5O2(g) ---> 3CO2(g) + 4H2O(g)

The balanced equation above shows the combustion of propane, C3H8 in oxygen, O2 to yield carbon dioxide, CO2 and water, H2O

The mole ratio of combustion are as follows:

1 mole of C3H8 react to produce 4 moles of H2O

1.55 mole of C3H8 will react to produce Z moles of H2O

To get the value of Z, cross multiply

Z x 1 mole = 1.55 mole x 4 mole

Z = 6.2 moles

Thus, 6.2 moles of water will be produced from 1.55 moles of propane

6 0
4 years ago
What types of reactions are these 3 chemical equations?-
IceJOKER [234]

Answer:

*2Kl+Pb(NO3)2=PbI2+2KNO3: double replacement.

*2Al+3CuSO4=Al2(SO4)3+3Cu: single replacement.

*C2H5OH+3O2=2CO2+3H2O: combustion.

Explanation:

Hello there!

In this case, according to the required, it turns out necessary for us to recall the five types of reactions, combination, decomposition, single and double replacement and combustion as shown on the attached figure.

In such a way, since the first reaction follows the pattern AB+CD-->AD+CB we infer it is double replacement; the second reaction follows the patter A+BC-->AC+B and therefore it is single replacement; and the last one follows the pattern of combustion reaction due to the presence of CO2 and H2O on the products side.

Regards!

3 0
3 years ago
A solution is prepared by combining 5.00 mL of 4.8x10-4 M NaSCN solution, 2.00 mL of 0.21 M Fe(NO3)3 solution and 13.00 mL of 0.
Tcecarenko [31]

Answer:

The analytical concentrations of thiocyanate ions:

[SCN^-]=0.00012 mol/L

The analytical concentrations of ferric ions:

[Fe^{3+}]=0.063 mol/L

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

1) Moles of sodium thiocyanate  = n

Volume of sodium thiocyanate solution = 5.00 mL = 0.005 L

(1 mL = 0.001L)

Molarity of the sodium thiocyanate = 4.8\times 10^{-4} M

n=4.8\times 10^{-4} M\times 0.005 L=2.4\times 10^{-6}mol

1 mole of sodium thiocyanate has 1 mol of thiocyante ions.

So, moles of thioscyanate ions in 2.4\times 10^{-6}mol  of NaSCN.

=1\times 2.4\times 10^{-6}mol=2.4\times 10^{-6}mol

2) Moles of ferric nitrate = n'

Volume of ferric nitrate solution = 2.00 mL = 0.002 L

Molarity of the ferric nitrate = 0.21 M

n'=0.002 M\times 0.21 L=0.00042 mol

1 mole of ferric nitrate has 3 moles of ferric ions.

So number of moles of ferric ions in 0.00042 moles of ferric nitrate is :

3\times 0.00042 mol=0.00126 mol

Volume of nitric acid = 13.00 mL

Total volume by adding all three volumes of solutions = V

V = 5.00 mL + 2.00 mL + 13.00 mL = 20.00 mL = 0.020 L

The analytical concentrations of thiocyanate ions:

[SCN^-]=\frac{2.4\times 10^{-6}mol}{0.020 L}=0.00012 mol/L

The analytical concentrations of ferric ions:

[Fe^{3+}]=\frac{0.00126 mol}{0.020 L}=0.063 mol/L

3 0
3 years ago
Read 2 more answers
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