Answer:17.47m
Explanation:
Explanation:
Molarity is defined as moles of solute per liters of solution.
c
=
n
V
Glacial acetic acid is actually anhydrous acetic acid, which implies that the acetic acid is not actually dissolved in a solvent and therefore is not ctually a solute.
However, you can still calculate its molarity based on the number of moles of you get per liter of glacial acetic acid.
To do that, start with a sample o
1.000 L
of glacial acetic acid. You know that at
25
∘
C
, glacial acetic acid has a density of
1.049 g/mL
, which tells you that every mililiter of glacial acetic acid has a mass of
1.049 g
.
This means that the mass of the sample will be
1.000
L
⋅
1000
mL
1.000
L
⋅
1.049 g
1
mL
=
1049 g
To find how many moles you get in the sample, use the given molar mass, which tells you how many grams of acetic acid you get per mole
1049
g
⋅
1 mole CH
3
COOH
60.05
g
=
17.469 moles CH
3
COOH
Now that you know the volume of the sample and how many moles it contains, you can say that
c
=
17.469 moles
1.000 L
=
17.47 M
I'll keep the number of sig figs given for the density of glacial acetic acid.
