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Sonbull [250]
1 year ago
12

Write an inequality that describes the graph. PLEASE HELP ASAP

Mathematics
1 answer:
Ugo [173]1 year ago
5 0

Answer:

When writing an inequality from a graph, there are a few things we need to do:

Determine the equation of the line. This gives us the general form of our inequality once we remove the equal sign.

Note whether the line is dotted or solid. ...

Use the graph's shading to determine which way you

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1+1-1......................help plz due in 20 secs
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1 is ur answer Step-by-step explanation:

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2 years ago
What is the final transformation in this sequence of transformations mapping pre-image VWXYZ to final image V''W''X''Y''Z''?
MatroZZZ [7]

Answer: d, a rotation 180 degrees about Z’

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3 years ago
Use the Remainder Theorem to find the remainder for (2x^3-3x^2+6)/(x-1) and state whether or not the binomial is a factor of the
Bezzdna [24]

Answer:

Remainder= 5, and the binomial (x-1) is not a factor of the given polynomial.

Step-by-step explanation:

Given polynomial is (2x^3-3x^2+6) , we have to divide this with a binomial [tex}(x-1)[/tex] using remainder theorem.

Remainder theorem says if (x-a) is a factor then remiander would be f(a)

Therefore for (x-1), \ {we find}\  f(1)}

f(1)=(2\times 1^3-3\times1^2+6)\\1^3 =1\\1^2=1\\Substituting \ this \ above\\f(1)= (2-3+6)=5

Thus the remainder is 5 and since it is not 0 , so the binomial (x-1) is not a factor of the given polynomial.

6 0
2 years ago
Read 2 more answers
Find all real zeros of 4x^3-20x+16
Pani-rosa [81]

Answer:

  {1, (-1±√17)/2}

Step-by-step explanation:

There are formulas for the real and/or complex roots of a cubic, but they are so complicated that they are rarely used. Instead, various other strategies are employed. My favorite is the simplest--let a graphing calculator show you the zeros.

___

Descartes observed that the sign changes in the coefficients can tell you the number of real roots. This expression has two sign changes (+-+), so has 0 or 2 positive real roots. If the odd-degree terms have their signs changed, there is only one sign change (-++), so one negative real root.

It can also be informative to add the coefficients in both cases--as is, and with the odd-degree term signs changed. Here, the sum is zero in the first case, so we know immediately that x=1 is a zero of the expression. That is sufficient to help us reduce the problem to finding the zeros of the remaining quadratic factor.

__

Using synthetic division (or polynomial long division) to factor out x-1 (after removing the common factor of 4), we find the remaining quadratic factor to be x²+x-4.

The zeros of this quadratic factor can be found using the quadratic formula:

  a=1, b=1, c=-4

  x = (-b±√(b²-4ac))/(2a) = (-1±√1+16)/2

  x = (-1 ±√17)2

The zeros are 1 and (-1±√17)/2.

_____

The graph shows the zeros of the expression. It also shows the quadratic after dividing out the factor (x-1). The vertex of that quadratic can be used to find the remaining solutions exactly: -0.5 ± √4.25.

__

The given expression factors as ...

  4(x -1)(x² +x -4)

5 0
2 years ago
Read 2 more answers
Solve the problem. Make sure your answer is in simplest form and improper fractions are expressed as mixed numbers. A packer fil
postnew [5]
Easy! Just multiply 7 1/3 by 8 which leaves you with 58 2/3. Now, that 1/4 is 1/4 of an hour. If you can fill 7 1/3 boxes in 1 hour, how many can you fill in 1/4? 7 1/3 divided by 1/4 is 29 1/3. Add them together. 81 boxes. 
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3 years ago
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