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PSYCHO15rus [73]
2 years ago
12

Answer the following questions…

Chemistry
1 answer:
Zina [86]2 years ago
3 0

The concentration of the hydronium ion in hydrochloric acid is 0.0045 M, and the pH of the solution is 2.34.

<h3>What is pH?</h3>

pH is the potential of the hydrogen or the hydronium ions in the aqueous solution.

As the solution contains 4.5 \times 10^{-3} \;\rm  M\; HCl the concentration of the hydronium ion will be the same, 4.5 \times 10^{-3} \;\rm  M.

The pH of the solution is calculated as:

\begin{aligned} \rm pH &= \rm -log[H^{+}]\\\\&= - \rm log (4.5 \times 10^{-3})\\\\&= 2.34\end{aligned}

The concentration of the hydroxide ion is calculated from pH and hydronium ion as:

\begin{aligned} \rm [H_{3}O^{+}][OH^{-}] &= 10^{-14}\\\\&= \dfrac{1 \times 10^{-14}}{4.5 \times 10^{-3}}\\\\&= 2.2 \times 10^{12}\end{aligned}

Now, for the calcium hydroxide solution, the calculations are shown as,

\begin{aligned} \rm (H_3}\rm O^{+}) &= \rm antilog (-pH)\\\\&= \rm antilog (-8)\\\\&= 10^{-8} \;\rm M\end{aligned}

pOH is calculated as:

\begin{aligned} \rm pOH &= 14- 8 = 6\\\\\rm [OH^{-}] &=  \rm antilog (-6)\\\\&= 10^{-6} \end{aligned}

The concentration of calcium hydroxide is calculated as:

\begin{aligned} &= \dfrac{1}{2} \times \rm [OH^{-}]\\\\&= 5 \times 10^{-4} \;\rm M\end{aligned}

Therefore, the pH and the pOH give the concentration of the hydrogen or the hydronium ion and the hydroxide ion.

Learn more about pH and pOH here:

brainly.com/question/16062632

#SPJ1

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A(g) + 2B(g) → C(g) + D(g)
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Answer:

0.169

Explanation:

Let's consider the following reaction.

A(g) + 2B(g) ⇄ C(g) + D(g)

We can find the pressures at equilibrium using an ICE chart.

       A(g) + 2 B(g) ⇄ C(g) + D(g)

I       1.00     1.00        0        0

C       -x        -2x        +x       +x

E    1.00-x  1.00-2x     x         x

The pressure at equilibrium of C is 0.211 atm, so x = 0.211.

The pressures at equilibrium are:

pA = 1.00-x = 1.00-0.211 = 0.789 atm

pB = 1.00-2x = 1.00-2(0.211) = 0.578 atm

pC = x = 0.211 atm

pD = x = 0.211 atm

The pressure equilibrium constant (Kp) is:

Kp = pC × pD / pA × pB²

Kp = 0.211 × 0.211 / 0.789 × 0.578²

Kp = 0.169

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