Saturn is about 1 429 000 km from the sun. how many meters is saturn from the sun?
2 answers:
You might be interested in
Answer : The enthalpy of the reaction is, -2552 kJ/mole
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given enthalpy of reaction is,
The intermediate balanced chemical reactions are:
(1)
(2)
(3)
(4)
Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :
(when we are reversing the reaction then the sign of the enthalpy change will be change.)
The expression for enthalpy of the reaction will be,
Therefore, the enthalpy of the reaction is, -2552 kJ/mole
Answer:
The molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.
Explanation:
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
where,
= osmotic pressure of the solution = 0.602 mbar = 0.000602 bar
0.000602 bar = 0.000594 atm
(1 atm = 1.01325 bar)
i = Van't hoff factor = 1 (for non-electrolytes)
c = concentration of solute = ?
R = Gas constant =
T = temperature of the solution =
Putting values in above equation, we get:
The concentration of solute is
Volume of the solution = V =0.137 L
Moles of β‑Galactosidase = n
To calculate the molecular mass of solute, we use the equation:
Moles of β‑Galactosidase =
Given mass of β‑Galactosidase= 0.387 g
Putting values in above equation, we get:
Hence, the molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.