The average atomic mass of her sample is 114.54 amu
Let the 1st isotope be A
Let the 2nd isotope be B
From the question given above, the following data were obtained:
- Abundance of isotope A (A%) = 59.34%
- Mass of isotope A = 113.6459 amu
- Mass of isotope B = 115.8488 amu
- Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
- Average atomic mass =?
The average atomic mass of the sample can be obtained as follow:
Thus, the average atomic mass of the sample is 114.54 amu
Learn more about isotope: brainly.com/question/25868336
The difference between the two is that the values in discontinuous variation are fixed, while the values in continuous variation can be changed. :)
Answer:
The partial pressure of helium gas in a gaseous mixture of helium and hydrogen is the pressure that the helium would exert in the absence of the hydrogen. equal to the total pressure divided by helium's molar mass. O equal to the total pressure divided by the number of helium atoms present.
Hope this Helps (✿◡‿◡)
A solution is a mixture (solvent + solute) of 2 or more elements, for example chocolate milk.
A solvent is the base of the solution which dissovles a solute, for example milk.
A solute is what is dossolved by the solvent, for example chocolate powder.
