Answer:
longer than visible light
Explanation:
Think about the formula for potential energy. (Surely you remember it):
Potential energy = (mass) x (acceleration of gravity) x (height)
-- The mass on the end of the pendulum doesn't change.
-- The acceleration of gravity doesn't change.
-- The only thing that changes is the height of the mass on the end.
So the potential energy is lowest when its height is the lowest.
That's position <em>B </em>.
Answer:
Young's modulus for the rope material is 20.8 MPa.
Explanation:
The Young's modulus is given by:

Where:
F: is the force applied on the wire
L₀: is the initial length of the wire = 3.1 m
A: is the cross-section area of the wire
ΔL: is the change in the length = 0.17 m
The cross-section area of the wire is given by the area of a circle:

Now we need to find the force applied on the wire. Since the wire is lifting an object, the force is equal to the tension of the wire as follows:

Where:
: is the tension of the wire
: is the weigh of the object = mg
m: is the mass of the object = 1700 kg
g: is the acceleration due to gravity = 9.81 m/s²

Hence, the Young's modulus is:
Therefore, Young's modulus for the rope material is 20.8 MPa.
I hope it helps you!
Answer:
All the statements are true
Explanation:
A) Wires are in tension.
It is true because the loads exerted on the bridge are taken by each of the cables of the bridge. these cables transmit the force to the pillars or columns of the bridge. (check the image 01)
B) Large posts are in compression.
It is true each of the loads of the cables is tension, are transmitted to the columns of the bridge, in this way the balance will be maintained (check the image 01)
C) The bridge deck is both in tension and compression.
Yes it is true, the superior part of the deck will be in compression and the inferior part will be in tension, this can be seen in the image 02
The frequency of the wave is 
Explanation:
The frequency, the wavelength and the speed of a wave are related by the following equation:

where
c is the speed of the wave
f is the frequency
is the wavelength
For the radio wave in this problem,


Therefore, the frequency is:

Learn more about waves here:
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