Answer:
The potential energy is transformed into kinetic energy
Explanation:
This particular case is defined as the principle of energy conservation since energy is not created or destroyed only transforms. When you have potential energy it can be transformed into kinetic energy or vice versa. In this problem, we have the case of a ball that sits on a desk and then falls to the ground. In this way the ground will be taken as a reference point, this is a point at which the potential energy will be equal to zero in such a way that when the ball is on the desktop that is above the reference line its potential energy will be maximum. As the ball drops its potential energy decreases, as the height relative to the ground (reference point) decreases. In contrast its kinetic energy increases and increases as it approaches the ground. So when it hits the ground it will have maximum kinetic energy and will be equal to the potential energy for when the ball was on the desk.
Therefore:
![E_{p} = potential energy [J] = E_{k} = kinetic energy [J]where:\\E_{p} =m*g*h\\m =mass [kg]\\g=gravity[m/s^2]\\h=elevation[m]\\E_{k} = \frac{1}{2} *m*v^{2} \\where:\\v=velocity [m/s]\\\frac{1}{2} *m*v^{2} = m*g*h](https://tex.z-dn.net/?f=E_%7Bp%7D%20%3D%20potential%20energy%20%5BJ%5D%20%3D%20E_%7Bk%7D%20%3D%20kinetic%20energy%20%5BJ%5Dwhere%3A%5C%5CE_%7Bp%7D%20%3Dm%2Ag%2Ah%5C%5Cm%20%3Dmass%20%5Bkg%5D%5C%5Cg%3Dgravity%5Bm%2Fs%5E2%5D%5C%5Ch%3Delevation%5Bm%5D%5C%5CE_%7Bk%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2Am%2Av%5E%7B2%7D%20%5C%5Cwhere%3A%5C%5Cv%3Dvelocity%20%5Bm%2Fs%5D%5C%5C%5Cfrac%7B1%7D%7B2%7D%20%20%2Am%2Av%5E%7B2%7D%20%3D%20m%2Ag%2Ah)
Answer: Most aerobic and strength training programs cause your muscles to contract and tighten. So stretching after you exercise helps optimize the range of motion about your joints and boosts circulation.
Hope this helps!
Answer:
Women's empowerment is all about equipping and allowing women to make life-determining decisions through the different problems in s
Answer:
μ₁ = 0.1048
μ₂ = 0.1375
Explanation:
Using static equation can find in both point the moment and the forces so:
∑ M = F *d , ∑ F = 0
∑ M A = 0
N₁ * 3 - 200 * 9.81 * 1.5 = 0
N₁ = 981
∑ M y = 0
N₂ + 300 * ³/₅ - 981 - 20 * 9.81 = 0
N₂ = 997.2 N
∑ M C = 0
F₁ * 1.75 - 300 * ⁴/₅ * 0.75 = 0
F₁ = 102.86
∑ M B = 0
300 * ⁴/₅ * 1 - F₂ * 1.75 = 0
F₂ = 137.14 N
The Force F1 and F2 related the coefficients of static friction
F₁ = μ₁ * N₁ ⇒ 102.86 N = μ₁ * 981 ⇒ μ₁ = 0.1048
F₂= μ₂ * N₂ ⇒ 137.14 N = μ₂ * 997 ⇒ μ₂ = 0.1375
When a satellite is moving around the Earth's orbit, two equal forces are acting on it. The centripetal and the centrifugal force. The centripetal force is the force that attracts the object toward the center of the axis of rotation. The opposite force is the centrifugal force. It draws the object away from the center. When these forces are equal, the satellite uniformly rotates along the orbit.
Centripetal force = Centrifugal force
Mass of satellite * centripetal acceleration = Mass of satellite * centrifugal acceleration
Centripetal acceleration = Centrifugal acceleration
ω^2r
where
= mass of earth
G = gravitational constant = 6.6742 x 10-11<span> m</span>3<span> s</span>-2<span> kg</span><span>-1
</span>
= radius of earth
ω = angular velocity
<span>r = radius of orbit
To convert to angular velocity:
</span>Tangential velocity = rω
ω = 5000/r
Then,
r = 2557110.465 m
Therefore, the distance of the centers of the earth and the satellite is
2.6 x 10^6 m.
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