Answer:
Taking more samples from different parts of an acre.
Explanation:
Validity and accuracy of the data is crucial for any serious research. In this particular case, the most accurate data would be obtained if earthworms would be counted on the whole acre. Of course, this would consume lot of time, people, money etc. That's why methods for estimation are used. Estimation best works with large number of samples. Since one acre equals over 4000 square meters, taking only five samples from such a big area is simply not enough for obtaining valid data.
One of the possible ways to improve estimation is to take more samples per acre while avoiding taking adjacent samples because it could be possible that number of earthworms in one part of an acre is increased (or decreased) for any reason, which would lead us to wrong conclusion.
Answer:
Uvula
Explanation:
The uvula is a fleshy structure found at the back of the soft palate in the mouth. It is the structure seen hanging at the back of the throat when someone opens his/her mouth and views in the mirror.
<em>The uvula is made up of flexible tissues with the ability to produce saliva. During eating or swallowing of food, the uvula along with the soft palate move to seal off the pharynx in order to prevent food materials from entering the nasal passage.</em>
Answer:
10
Explanation:
The cell cycle is composed of three states: interphase, cell division and resting.
The interphase is composed of 3 phases: G1, S and G2 (in this order). During this state the cell prepares itself for cell division. As part of the preparation the cell duplicates all its genetic material, that is, all its chromosomes. This duplication is done during the phase S.
During the meiotic cell division (composed of meiosis 1 and meiosis 2) a single diploid mother cell (with duplicated chromosomes) produces four haploid daughter cells. the meiosis 1 produces two haploid cells with duplicated chromosomes, and the meiosis 2 produces 4 haploid cells with normal chromosomes (no duplicated).
If a germ-line cell from a frog contains 10 picograms of DNA during G1, then this cell will have 20 picograms of DNA before the product of the first meiotic division, and will have 10 picograms at the begining of the meiosis 2 (i.e prophase II)
