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natka813 [3]
2 years ago
9

(2/3 - 3/4 × 1/8) ÷ (2/3 - 3/4 + 5/8)

Mathematics
2 answers:
inn [45]2 years ago
6 0

answer:

as improper fraction= 55/52

as mixed fraction= 1 3/52

hope this helps

kati45 [8]2 years ago
3 0
<h3>Given:</h3>

( \frac{2}{3}  -  \frac{3}{4}  \times  \frac{1}{8} ) \div ( \frac{2}{3}  -  \frac{3}{4}  +  \frac{5}{8} )

<h3>Solution:</h3>

First, solve the brackets.

First bracket:

( \frac{2}{3}  -  \frac{3}{4}  \times  \frac{1}{8} )

=  \frac{55}{96}

Second bracket:

( \frac{2}{3}   - \frac{3}{4}  +  \frac{5}{8} )

=  \frac{13}{24}

Then divide.

\frac{55}{96}  \div  \frac{13}{24}

=  \frac{55}{52}  \: or \:  1\frac{3}{52}

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A home alarm system randomly assigns a five-character code for each customer. The code will not repeat a character. The characte
ahrayia [7]

Answer:

The total number of codes which can be assigned is, 55440 .

Step-by-step explanation:

According to the question, the home alarm system randomly assigns a five-character code for each customer.The code will not repeat a character and there are 11 distinct characters.

So, the total number of codes that can be randomly assigned is given by,

^{11}{P}_{5}

= \frac {11!}{6!}

= 11 \times 10 \times 9 \times 8 \times 7

= 55440

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3 years ago
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Sveta_85 [38]

Answer:

x = - \frac{11}{2}

divide each term by two and simplify.

Give me my milf.

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3 years ago
Given the vent diagram below , if a student is randomly selected , what is the probability that he or she is not attending eithe
Furkat [3]
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3 years ago
Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC
Marysya12 [62]

BC is 10 units and AC is 5+5\sqrt{3} units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

  • \frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}
  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}

- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0
3 years ago
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