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2 years ago

What is nuclear fission?

Physics

2 answers:

padilas [110]2 years ago

7 0

Answer:

<em><u>a nuclear reaction in which a heavy nucleus splits spontaneously or on impact with another particle, with the release of energy.</u></em>

Explanation:

Hope it will help you

Vilka [71]2 years ago

4 0

Answer:

The process of breaking down of heavy nucleus into lighter ones is called nuclear fission.Similarly,the proces of combining lighter nucleus to heavy nucleus is also called nuclear fission.

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Block A of mass M is on a horizontal surface of negligible friction. An identical block B is attached to block A by a light stri

miv72 [106K]

Answer:

T’= 4/3 T

The new tension is 4/3 = 1.33 of the previous tension the answer e

Explanation:

For this problem let's use Newton's second law applied to each body

Body A

X axis

T = m_A a

Axis y

N- W_A = 0

Body B

Vertical axis

W_B - T = m_B a

In the reference system we have selected the direction to the right as positive, therefore the downward movement is also positive. The acceleration of the two bodies must be the same so that the rope cannot tension

We write the equations

T = m_A a

W_B –T = M_B a

We solve this system of equations

m_B g = (m_A + m_B) a

a = m_B / (m_A + m_B) g

In this initial case

m_A = M

m_B = M

a = M / (1 + 1) M g

a = ½ g

Let's find the tension

T = m_A a

T = M ½ g

T = ½ M g

Now we change the mass of the second block

m_B = 2M

a = 2M / (1 + 2) M g

a = 2/3 g

We seek tension for this case

T’= m_A a

T’= M 2/3 g

Let's look for the relationship between the tensions of the two cases

T’/ T = 2/3 M g / (½ M g)

T’/ T = 4/3

T’= 4/3 T

The new tension is 4/3 = 1.33 of the previous tension the answer e

4 0

3 years ago

What does the word “adverse” mean in the following sentence? Adverse reactions, such as fever and headache, can occur if the med

Stells [14]

I think it's D. unfavorable hope it helps

3 0

3 years ago

Read 2 more answers

(11%) Problem 5: A uniform stationary ladder of length L = 2.7 m and mass M = 11 kg leans against a smooth vertical wall, while

jeka94

Answer:

970.2 N

Explanation:

We are given that

Length of ladder=2.7 m

Mass,M=11 kg

Coefficient of friction= $\mu=0.45$

$\theta=51^{\circ}$

Mass of painter=8M

Distance from base=d

We have to find the magnitude of the normal force exerted by the floor on the ladder.

Normal force exerted by floor on the ladder= $mg+8mg=9mg$

Where $g=9.8m/s^2$

Normal force exerted by floor on the ladder= $9\times 11\times 9.8=970.2N$

7 0

3 years ago

A fan blade, initially at rest, rotates with a constant acceleration of 0.029 rad/s2. What is the time interval required for it

LenKa [72]

Answer:

The time interval is $t = 21.30 \ s$

Explanation:

From the question we are told that

The constant acceleration is $\alpha = 0.029 \ rad / s^2$

The displacement is $\theta = 6.58 \ rad$

According to the second equation of motion we have that

$\theta = w_i* t + \frac{1}{2} * \alpha t^2$

given that the blade started from rest

$w_i$ which is the initial angular velocity is 0

$\theta = 0 + \frac{1}{2} * \alpha t^2$

=> $t = \sqrt{ \frac{2 * \theta }{\alpha } }$

substituting values

=> $t = \sqrt{ \frac{2 * 6.58 }{0.029 } }$

=> $t = 21.30 \ s$

6 0

3 years ago

758 j of heat are added to 0.750 kg of copper. how much does its temperature change?(unit=degrees c) PLEASE HELPPPPPPP MEEEEEE

DiKsa [7]

Answer:

$2.6^{\circ}C$

Explanation:

When a substance is supplied with a certain amount of heat energy, the temperature of the substance increases according to the equation

$Q=mC\Delta T$

where

m is the mass of the substance

Q is the amount of energy supplied

C is the specific heat of the substance

$\Delta T$ is the temperature change

In this problem:

Q = 758 J is the energy supplied

m = 0.750 kg is the mass of the sample

$C=385 J/kg^{\circ}C$ is the specific heat of copper

Re-arranging the equation, we can find the increase in temperature:

$\Delta T=\frac{Q}{mC}=\frac{758}{(0.750)(385)}=2.6^{\circ}C$

5 0

3 years ago

What is nuclear fission?​

What is nuclear fission?