Answer:
I'm pretty sure this is not a complete question. My guess is that you are trying to add/subtract vectors. Vectors have both magnitude and direction, so vector A is pretty clear, but a magnitude of 13 (i'm guessing a resultant) without a direction is weird.
IF 13 is the magnitude of the resultant, vector B added to vector A could have any magnitude 17 ≤ B ≤ 43
It could have any direction of
θ = (225 - 180) ± arcsin(13/30)
θ = 45 ± 25.679...
70.679 ≤ θ ≤ 19.321
components of vector B would be
Bx = |B|cosθ
By = |B|sinθ
Answer:
I think it's the most important part in this
Answer:
51.96 m/s^-1
Explanation:
a) see the attachment
b) As we know the velocity of the projectile has two component, horizontal velocity v_ox. and vertical velocity v_oy as shown in the figure. At the highest point of the trajectory, the projectile has only horizontal velocity and vertical velocity is zero. Therefore at the highest point of the trajectory, the velocity of the projectile will be
v_ox=v_o*cosФ
=60*cos (30)
= 51.96 m/s^-1
The truck would of went 150 miles
You are looking at yourself in a plane mirror, a distance of 3 meters from the mirror. your brain interprets what you are seeing in the mirror as being a person standing 6 meters from you.
<h3>Calculation</h3>
The plane mirror shows an exact replica of the real world. that means the distance of you from the mirror is the same distance as your reflection form the mirror at the opposite side of the mirror.
Thus, distance of image from the plane mirror is same as the distance of object (person) from the plane mirror but the image is formed behind the mirror.
Thereby we have v=u=3 m
Thus, distance between image and the person
is d = v + u = 3 + 3 = 6 m
Thus, the person is 6 meters away from the image.
To know more such mirror problems, visit:
brainly.com/question/14687229
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