Let us assume that there are 100 grams of substance present. The masses of the constituents will be:
C - 58.51 g
H - 7.37 g
N - 100 - 58.51 - 7.37 = 34.12 g
Next, we determine the moles of each substance by dividing by the atomic masses:
C - 58.51/12 = 4.88
H - 7.37/1 = 7.37
N - 34.12/14 = 2.44
Dividing all of the moles by the lowest number of moles, which is 2.44 of nitrogen, we get the ratio:
C - 2
H - 3
N - 1
The empircal formula becomes C₂H₃N
Next, we apply Graham's Law of diffusion, which mathematically is:
v₁/v₂ = √M₂ / √M₁
Let species 1 be helium, meaning v₁/v₂ = 3.2 and M₁ = 4
3.2 = √M₂ / √4
M₂ = 40.96
The mass of the empircal formula was:
12 * 2 + 1 * 3 + 14 = 41
The empircal formula is the molecular formula as their masses are approximately the same. This compound is C₂H₃N
Answer:
what are the options to the question
Answer:
The major forces acting in an atom are the strong force, the weak force and the electromagnetic force. Electromagnetic forces of attraction and repulsion based on charges keep the subatomic particles and make them move.These forces are also responsible for energy levels of electrons and their positions.
Explanation:
Lewis structure of N2O5 is :
:O : : O:
II II
N N
/ \ / \
:O: :O: :O :
.. ..
or or O2 N-O- NO2
<span>So the covalency of nitrogen is 3 only as one pair of electrons is coordinated with oxygen shown here as having all the six electrons intact.
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Answer:
ΔS > 0 only for choice E: CH4(g) + H2O (g) → CO(g) + 3 H2(g)
Explanation:
Our strategy in this question is to use the trend in entropies :
S (solids) less than S (liquids) less than S (gases)
Also we have to look for the molar quanties involved of each state and their change to answer the question:
A. N2(g) + 3 H2(g) → 2 NH3(g)
Here we have 4 moles gases going to 2 moles of products, so the change in entropy is negative.
B. Na2CO3(s) + H2O(g) + CO2(g) → 2 NaHCO3(s)
The change in entropy is negative since we have 2 mol gases in the reactants and zero in the products.
C. CH3OH(l) → CH3OH(s)
A liquid has a higher entropy than a solid so ΔS is negative
D. False see A,B,C
E. The change in moles of gases is 4 - 2= 2, therefore ΔS is greater than O.