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solmaris [256]
2 years ago
15

State Coulomb’s Law equation and give the meaning of every variable and the units.

Physics
1 answer:
igor_vitrenko [27]2 years ago
5 0

The Coulomb's law equation is  F = Kq₁q₂/r².

<h3>What is Coulomb's law?</h3>

This is the law that relates the product of two charges to the square of distance between the two charges.

Coulomb's law states that the force of attraction or repulsion is directly proportional to the product of the charges and inversely proportional to the square of distance between the charges.

<h3>Coulombs' law equation</h3>

The equation of Coulomb's law is given as;

F = Kq₁q₂/r²

where;

  • K is Coulomb's constant, Nm²/C²
  • q₁ is the first charge, C
  • q₂ is the second charge, C)
  • r is the distance between the charges, m

Thus, the Coulomb's law equation is  F = Kq₁q₂/r².

Learn more about Coulomb's law equation here: brainly.com/question/24743340

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Answer:

C) three

Explanation:

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for copper

heat absorbed = 1 x .385 x Δt

for gold

heat absorbed = m x .129 x Δt

So

m x .129 x Δt = 1 x .385 x Δt

m = 2.98

= 3 g approximately .

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A projectile is fired with an initial velocity of 450 feet per second at an angle of 70° with the horizontal.
pav-90 [236]
<h2>After 26.28 seconds projectile returns 26.28 seconds.</h2>

Explanation:

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Angle, θ = 70°

Consider the vertical motion of projectile,

When the projectile return to the ground we have

           Displacement, s = 0 m

           Acceleration, a = -9.81 m/s²

            Initial velocity, u = 137.16 x sin70 = 128.89 m/s

Substituting in s = ut + 0.5 at²

                s = ut + 0.5 at²

                0 = 128.89 x t + 0.5 x (-9.81) x t²

                t² - 26.28 t = 0

                t ( t- 26.28) = 0

               t = 0 s or t = 26.28 s

After 26.28 seconds projectile returns 26.28 seconds.

5 0
3 years ago
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