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Monica [59]
3 years ago
15

Which change will cause the gravitational force between a baseball and a soccer ball to increase ? Check all that apply

Physics
2 answers:
raketka [301]3 years ago
8 0

Explanation :

We know that the gravitational force between two objects is given by :

F=G\dfrac{m_1m_2}{r^2}

where,

G is universal gravitational constant.

m_1 and m_2 are the masses of two objects.

r is the distance between them

i.e. F\propto m_1m_2

and F\propto \dfrac{1}{r^2}

So, the correct options are :

(1) Moving the balls closer together. The distance decreases and force increases.

(3) Wrapping the soccer ball in layers of duct tape will also increase force because the mass will increase.

(5) Similarly, putting the baseball in a plastic case will increase mass and hence force increases.

Alex73 [517]3 years ago
4 0
Moving the balls closer together pumping more air into the soccer ball putting the baseball in a plastic case 
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You carry a fire hose up a ladder to a height of 10 m above ground level and aim the nozzle at a burning roof that is 9 m high.
schepotkina [342]

Answer:

The value is P_1  = 314645 \ Pa

Explanation:

From the question we are told that

The height is h_2  =  10  m

The height of the burning roof is k  =  9  m

The horizontal distance is d =  7 \  m

The height of the truck is h_1  =  0.5 \  m

Generally the time for the water to hit the roof from the hose is mathematically represented as

t =  \sqrt{\frac{2 *  (h_2 - k)}{g} }

=> t =  \sqrt{\frac{2 *  (10  - 9)}{9.8} }

=> t = 0.4518 \ s

Generally the velocity of the water is mathematically evaluated as

v_2  =  \frac{d}{t}

v_2  =  \frac{ 7}{0.4518}

v_2  =  15.5 \  m/s

Generally from Bernoulli's Equation we have that

P_1  + \frac{1}{2} v_1^2 * \rho + \rho *g *h_1  = P_2  + \frac{1}{2} v_2^2 * \rho + \rho *g *h_2

Here P_1 [\tex] is pressure in the chamber which we are to calculate , [tex]P_2 [\tex] is the atmospheric pressure with value  [tex]P_2 =  101325 \ Pa  [\tex] , [tex]v_1 [\tex] is the velocity of the water before it starts flowing with value [tex]v_1  =  0 m/s [\tex] , [tex]\rho [\tex]  is the density of water with value [tex]\rho =  1000 \ kg/m^3  [\tex] So         [tex]P_1  + \frac{1}{2} 0^2 * 1000 + 1000 *9.81 *0.5 = 101325  + \frac{1}{2}* 15.5^2* 1000 + 1000 *9.81 *10  

         P_1  = 314645 \ Pa        

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Sidana [21]

Answer:

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Explanation:

Given parameters:

Mass of car  = 2000kg

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According to Newton's second law of motion, Force is a product of mass and acceleration.

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Now, insert the parameters and find the unknown;

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