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Monica [59]
3 years ago
15

Which change will cause the gravitational force between a baseball and a soccer ball to increase ? Check all that apply

Physics
2 answers:
raketka [301]3 years ago
8 0

Explanation :

We know that the gravitational force between two objects is given by :

F=G\dfrac{m_1m_2}{r^2}

where,

G is universal gravitational constant.

m_1 and m_2 are the masses of two objects.

r is the distance between them

i.e. F\propto m_1m_2

and F\propto \dfrac{1}{r^2}

So, the correct options are :

(1) Moving the balls closer together. The distance decreases and force increases.

(3) Wrapping the soccer ball in layers of duct tape will also increase force because the mass will increase.

(5) Similarly, putting the baseball in a plastic case will increase mass and hence force increases.

Alex73 [517]3 years ago
4 0
Moving the balls closer together pumping more air into the soccer ball putting the baseball in a plastic case 
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A or C    I would pick C

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An oscillator consists of a block attached to a spring (k = 427 N/m). At some time t, the position (measured from the system's e
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Answer:

a) 4.49Hz

b) 0.536kg

c) 2.57s

Explanation:

This problem can be solved by using the equation for he position and velocity of an object in a mass-string system:

x=Acos(\omega t)\\\\v=-\omega Asin(\omega t)\\\\a=-\omega^2Acos(\omega t)

for some time t you have:

x=0.134m

v=-12.1m/s

a=-107m/s^2

If you divide the first equation and the third equation, you can calculate w:

\frac{x}{a}=\frac{Acos(\omega t)}{-\omega^2 Acos(\omega t)}\\\\\omega=\sqrt{-\frac{a}{x}}=\sqrt{-\frac{-107m/s^2}{0.134m}}=28.25\frac{rad}{s}

with this value you can compute the frequency:

a)

f=\frac{\omega}{2\pi}=\frac{28.25rad/s}{2\pi}=4.49Hz

b)

the mass of the block is given by the formula:

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}\\\\m=\frac{k}{4\pi^2f^2}=\frac{427N/m}{(4\pi^2)(4.49Hz)^2}=0.536kg

c) to find the amplitude of the motion you need to know the time t. This can computed by dividing the equation for v with the equation for x and taking the arctan:

\frac{v}{x}=-\omega tan(\omega t)\\\\t=\frac{1}{\omega}arctan(-\frac{v}{x\omega })=\frac{1}{28.25rad/s}arctan(-\frac{-12.1m/s}{(0.134m)(28.25rad/s)})=2.57s

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x=Acos(\omega t)\\\\A=\frac{0.134m}{cos(28.25rad/s*2.57s )}=0.45m

5 0
2 years ago
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Answer:

it helps with balance and speed.

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3 0
3 years ago
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A spring has a equilibrium length of 10.0 cm. When a force of 40.0 N is applied to the spring, the spring has a length of 14.0 c
mote1985 [20]

Answer:

The value of the spring constant of this spring is 1000 N/m

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Answer:

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Explanation:

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