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DIA [1.3K]
2 years ago
7

The periodic table has undergone some changes since it was first introduced. List three ways the modern periodic table differs f

rom the one first published by Mendeleev in 1869.
I have two of the three ways:
1: updating the atomic weight
2: adding newly discovered elements

However, I cannot come up with a last way the modern periodic table differs from Mendeleev's. Please help (:
Chemistry
1 answer:
Hoochie [10]2 years ago
6 0
One of the differences I can think of is that hydrogen is no longer listed as a group I element.

According to the mendeleev tables that I looked up, hydrogen is catorgrized as a group I element, along with Lithium, sodium, Potassium etc. However, nowadays, hydrogen does not belong to any groups in the periodic table. This is because there are arguments about whether hydrogen belongs to group I. Group I elements are all alkali metals, while hydrogen is not. However, some people says that hydrogen only have one outer shell electron so it should be in group I. Some people even say hydrogen should belong to group VII because it only needs one more electron in order to achieve the duplet of electrons.

Therefore as you may notice, hydrogen in modern periodic tables are put in the center of the periodic table on the top.
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    b. This is a double- replacement reaction. (The elements "switch partners".)

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3 years ago
The Earth's period of revolution is 365.25 days. Convert this period of revolution into hours
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3 years ago
What is the molality of a solution if 100.0 g of glucose (C&Hi20e) were dissolved into 750. mL of water?
hodyreva [135]

<u>Answer:</u> The molality of solution is 0.740 m.

<u>Explanation:</u>

To calculate the mass of solvent (water), we use the equation:

Density=\frac{Mass}{Volume}

Volume of water = 750 mL

Density of water = 1 g/mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{750mL}\\\\\text{Mass of water}=750g

To calculate the molality of solution, we use the equation:

Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (C_6H_{12}O_6) = 100.0 g

M_{solute} = Molar mass of solute (C_6H_{12}O_6) = 180 g/mol

W_{solvent} = Mass of solvent (water) = 750 g

Putting values in above equation, we get:

\text{Molality of }C_6H_{12}O_6=\frac{100\times 1000}{180\times 750}\\\\\text{Molality of }C_6H_{12}O_6=0.740m

Hence, the molality of solution is 0.740 m.

6 0
3 years ago
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