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2 years ago

Whats the effect?

Chemistry

2 answers:

scZoUnD [109]2 years ago

6 0

Answer: A wave

Explanation:

Because it’s the one that’s cause the new medium to go between the two media.

Ivenika [448]2 years ago

5 0

Wave A! I hope this helps :)

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Methionine, ch3sch2ch2ch(nh2)co2h, is an amino acid found in proteins. what is the hybridization type of each carbon, oxygen, th

Lady_Fox [76]

Answer 1) To find the hybridization of carbon we need to draw the lewis structure first; which is attached in the answer.

So the formula for finding hybridization is
Lone pairs + Bonding pairs = hybridisation.

Here, in the molecule of methionine Carbon is bonded to all 4 atoms and has got no lone pairs so we will have;

0 + 4 = 4 which means it is $sp^{3}$ hybridized.

Answer 2) For oxygen we can see in the lewis structure that it is having 2 lone pairs and double bonded with carbon atom, also there is another oxygen atom with two lone pair but bonded with carbon and hydrogen at the end.

So, in both the cases we can calculate;

where 2 lone pairs are present
2 + 2 = 4 so, it will be $sp^{3}$ hybridized.

So, Oxygen is also $sp^{3}$ hybridized.

Answer 3) Nitrogen present in the methionine is bonded to carbon atom and hydrogen atoms and has only one lone pair on it.

So when we are substituting this in the formula we get 1 + 3 = 4;

which means 1 lone pair and 3 bond pairs so, it is also $sp^{3}$ hybridized.

Answer 4) Sulfur atom in methionine is bonded to two carbon atoms forming a linear structure with 2 lone pairs on it.

So, it has 2 lone pairs and 2 bond pairs,

hence the hybridization will be   $sp^{3}$ hybridized.

As, 2 + 2 = 4 which means it is   $sp^{3}$ hybridized.

5 0

2 years ago

Determine the change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizi

uysha [10]

Answer: The change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizing compound is dissolved in it is $2.9^0C$

Explanation:

Elevation in boiling point:

$T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of pure carbon disulfide= $46.2^oC$

$k_b$ = boiling point constant = $2.34^0Ckg/mol$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

$w_2$ = mass of solute = 35.0 g

$w_1$ = mass of solvent (carbon disulphide) = 397.7 g

$M_2$ = molar mass of solute = 70.0 g/mol

Now put all the given values in the above formula, we get:

$(T_b-46.2)^oC=1\times (2.34^oC/m)\times \frac{(35.0g)\times 1000}{70.0\times (397.7g)}$

$T_b=49.1^0C$

Therefore, the change in boiling point is $(49.1-46.2)^oC=2.9^0C$

5 0

3 years ago

How did Ernest Rutherford’s experiment relate to J.J. Thomson’s work?

horsena [70]

Thomson realized that the accepted model of an atom did not account for negatively or positively charged particles. Therefore, he proposed a model of the atom which he likened to plum pudding. ... Rutherford with the assistance of Ernest Marsden and Hans Geiger performed a series of experiments using alpha particles.

8 0

2 years ago

Red light has a wavelength of 700 nm and a frequency of 4.3 x 10^14 s^-1. What is the energy of a single photon of red light?

BaLLatris [955]

Answer:

E = 2.85×10⁻¹⁹ J

Explanation:

Given data:

Wavelength of light = 700 nm

Frequency of light = 4.3×10¹⁴ s⁻¹

What is the energy of light = ?

Solution:

Formula:

E = h × f

h = plancks constant = 6.63×10⁻³⁴ Js

by putting values,

E = 6.63×10⁻³⁴ Js × 4.3×10¹⁴ s⁻¹

E = 28.5×10⁻²⁰ J

E = 2.85×10⁻¹⁹ J

6 0

2 years ago

What is the symbol for gold

Slav-nsk [51]

The elemental symbol of gold is denoted on the periodic table as being Au.

5 0

3 years ago