Answer:
I just took the quiz and got 100% when choosing A.Conservation. Hope this helps:)
Givens
=====
Ti = 92.8 oC = 92.8 + 273 = 365.8
T2 = 0.4 oC = 0.4 + 273 = 273.4
Vi = 1.54 mL
Vf = ?????
Formula
======
Vi/Ti = Vf / Tf
1.54 / 365.8 = Vf / 273.4
Calculations
=========
1.54 * 273.4 / 355.8 = Vf
vf = 1.15 mL
Comment
=======
if your teacher is concerned about sig digs, the answer is 1 mL. I'm not sure how to show that it is 1 sig dig. You can ask about this.
Answer:
The car exerts a force on the truck which is c.) 6000 N.
Explanation:
If the truck exerts a force of 6000 N on the car then according to Newton's Third Law of Motion that every action has an equal and opposite reaction we can say that the force exerted by the car on the truck is 6000 N.
The only reason the truck is able to move the car is because of the frictional forces. That is frictional force of the trucks tires on the surface of the road and the frictional forces of the cars tire on the surface of the road, and since these forces are not equal this therefore gives rise to motion.
Let:
Vx = the pulling component of force
Vy = the lifting component of force
Vy:
Sin(n°) = Vy/hypotenuse
hypotenuse * Sin(n°) = Vy
100N*sin(30°) = Vy
50N = Vy
Vx:
Cos(n°) = Vx/hypotenuse
Hypotenuse * cos(n°) = Vx
100N*cos(30°) =Vx
about 86.6N = Vx
