Answer: 0.04139m
Explanation:
First, we need to calculate the weight of the man which will be:
Weight = mass × acceleration due to gravity
Weight = mg
Weight = 92.5 × 9.8
Weight = 906.5N
Then, we calculate the force which will be:
F = kx
mg = kx
x = mg/k
x = 906.5/21900
x = 0.04139m.
The spring stretched for 0.04139m.
Answer:
0.558 atm
Explanation:
We must first consider that both gases behaves like ideal gases, so we can use the following formula: PV=nRT
Then, we should consider that, whithin a mixture of gases, the total pressure is the sum of the partial pressure of each gas:
P₀ = P₁ + P₂ + ....
P₀= total pressure
P₁=P₂= is the partial pressure of each gass
If we can consider that each gas is an ideal gas, then:
P₀= (nRT/V)₁ + (nRT/V)₂ +..
Considering the molecular mass of O₂:
M O₂= 32 g/mol
And also:
R= ideal gas constant= 0.082 Lt*atm/K*mol
T= 65°C=338 K
4.98 g O₂ = 0.156 moles O₂
V= 7.75 Lt
Then:
P°O₂=partial pressure of oxygen gas= (0.156x0.082x338)/7.75
P°O₂= 0.558 atm
The concept to develop this problem is the Law of Malus. Which describes what happens with the light intensity once it passes through a polarized material.
Mathematically this can be expressed as
Where
I = New intensity after pass through the Polarizer
= Original intensity
= Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.
When the light passes perpendicularly through the first polarizer, the light intensity is reduced by half which will cause the intensity to be 
at the output of the new polarizer, mathematically:
Solving to find the angle we have
The orientation angle of the second polarizer relative to the first one is 43.11°
Answer:
v = 666.667 m/s
Explanation:
<u>Given</u>: length L = 25 cm = 0.25 m, B = 600 G = 0.06 T ( 1G = 0.0001 T)
emf= 10 V
Solution:
emf = vBL
v= emf / BL
v = 10 V / (0.06 T× 0.25 m)
v = 666.667 m/s
Answer:Combustion
Explanation:The chemical reaction is called combustion and requires oxygen. Combustion changes the potential chemical energy into kinetic energy in form of heat.
