The net force applied to it is 6311.9 N.
To calculate the net force to the car, first, we need to find the acceleration using the equation of motion.
Force: This as be defined as the product of mass and acceleration of a body. The S.I unit of force is Newton (N)
⇒ Formula
- S = ut+at²/2................. Equation 1
⇒ Where:
- u = Initial velocity
- S = Distance
- t = Time
- a = acceleration
From the question,
⇒Given:
- S = 40 m
- t = 3.0 s
- u = 0 m/s (at rest)
⇒ Substitute these values into equation 1
⇒ Solve for a
- 9a = 80
- a = 80/9
- a = 8.89 m/s²
⇒ To get the force, we use the formula below
- F = ma .................... Equation 2
⇒ Where:
- F = Force applied
- m = mass of the car
⇒ Given:
⇒ Substitute these values into equation 2
Hence the net force applied to it is 6311.9 N.
Learn more about force here: brainly.com/question/13370981
Answer:
Explanation:
Capacitance of capacitor
= ε₀ A / d , ε₀ is permittivity of space , A is area of plate , d is distance between plates.
= 8.85 x 10⁻¹² x 2 x 10⁻³ / (6 x 10⁻³)
= 2.95 x 10⁻¹² F
Electric field E = V / d , V is potential difference
V = E x d
= 100 x 10³ x 6 x 10⁻³
= 600 V
Charge on the capacitor
= capacitance x potential difference
= 2.95 x 10⁻¹² x 600
= 17.7 x 10¹⁰ C
Answer:
a) -1.25 m/s²
b) 62.5 m
Explanation:
Convert km/h to m/s:
45 km/h × (1000 m/km) × (1 h / 3600 s) = 12.5 m/s
a = Δv / Δt
a = (0 m/s − 12.5 m/s) / 10 s
a = -1.25 m/s²
Δx = ½ (v + v₀) t
Δx = ½ (0 m/s + 12.5 m/s) (10 s)
Δx = 62.5 m
Answer:50.39 m/s,
40.46 m
Explanation:
Given
launch angle
Range=240 m
We know that Range 
u=50.39 m/s
(b)maximum height of projectile is given by
H=40.46 m
From the curve on the graph we can see, when y=50 x=4.5
the unit of x-axis is in "billions of years", so the answer is 4.5 billions of years
