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Sedaia [141]
3 years ago
7

A truck is using a hook to tow a car whose mass is one quarter that of the truck. If the force exerted by the truck on the car i

s 6000 N, then the force exerted by the car on the truck isa. 1500 Nb, 24000 Nc, 6000 Nd, 12000 N
Physics
1 answer:
strojnjashka [21]3 years ago
7 0

Answer:

The car exerts a force on the truck which  is c.)  6000 N.

Explanation:

If the truck exerts a force of 6000 N on the car then according to Newton's Third Law of Motion that every action has an equal and opposite reaction we can say that the force exerted by the car on the truck is 6000 N.

The only reason the truck is able to move the car is because of the frictional forces. That is frictional force of the trucks tires on the surface of the road and the frictional forces of the cars tire on the surface of the road, and since these forces are not equal this therefore gives rise to motion.

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A. The target nucleus split into two nuclei, each with fewer nucleons than the original.

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A plastic box has an initial volume of 2.00 m 3 . It is then submerged below the surface of a liquid and its volume decreases to
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Answer:

Volume strain is 0.02

Explanation:

Volume strain is defined as the change in volume to the original volume.

It is given that,

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We need to find the volume strain on the box. It is defined as the change in volume divided by the original volume. So,

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Which component of a galaxy consists of tiny particles that look smoky or cloudy and
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A passenger compartment of a rotating amusement park ride contains a bench on which a book of mass
Basile [38]

a) 120 s

b) v = 0.052R [m/s]

Explanation:

a)

The period of a revolution in a simple harmonic motion is the time taken for the object in motion to complete one cycle (in this case, the time taken to complete one revolution).

The graph of the problem is missing, find it in attachment.

To find the period of revolution of the book, we have to find the time between two consecutive points of the graph that have exactly the same shape, which correspond to two points in which the book is located at the same position.

The first point we take is t = 0, when the position of the book is x = 0.

Then, the next point with same shape is at t = 120 s, where the book returns at x = 0 m.

Therefore, the period is

T = 120 s - 0 s = 120 s

b)

The tangential speed of the book is given by the ratio between the distance covered during one revolution, which is the perimeter of the wheel, and the time taken, which is the period.

The perimeter of the wheel is:

L=2\pi R

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