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zvonat [6]
3 years ago
11

What is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°c to 70.0°c when 2,520 j of hea

t is applied? use q equals m c subscript p delta t.. 0.00420 j/(gi°c) 0.00661 j/(gi°c) 238 j/(gi°c) 252 j/(gi°c)
Chemistry
2 answers:
Oliga [24]3 years ago
8 0

Answer:

4.2 j/kg-C      =  .0042 j / (g-C)

Explanation:

Specific heat units are    j / kg-C

   2520 J  / [ (10 kg)(70-10 C)]   = 4.2   j / kg-C

LekaFEV [45]3 years ago
5 0

Answer:

0.00420

Explanation:

The equation is Q=mc(T(final)-T(initial), where c is the specific heat, Q is heat supplied, m is mass, T(final) is final temperature and T(initial) is initial temperature (you'll see this written as delta T, which means change in temperature).

2520 = Q

m = 10.0kg; answer choices are in g, not kg, so multiply by 1000 to get m in g; m = 10000 g

Plug in the values you have and solve for c.

2520=(10000)(c)(70-10)

2520=600000c

c=0.0042 j/(gc)

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balu736 [363]

The given question is incomplete. The complete question is:

How much heat is produced when 24.8 g of CH_4 is burned in excess oxygen gas

Given: CH _4
+2O_2\rightarrow CO_2+2H_2O  ΔH= −802 kJ.

Answer: 1243.1 kJ

Explanation:

Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.

Given :

Amount of heat released on combustion of  1 mole of methane = 802 kJ kJ/mol

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of CH_4 weighs = 16 g  

Thus we can say:  

16 g of CH_4 on combustion releases heat = 802 kJ

Thus 24.8 g of CH_4 on combustion releases =\frac{802}{16}\times 24.8=1243.1kJ

Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ

4 0
3 years ago
How many branches of chemistry are there .​
faltersainse [42]

Answer:

5

Explanation:

Analytical chemistry

Organic chemistry

Inorganic chemistry

physical chemistry

Biochemistry

6 0
3 years ago
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Myth: A dead organism is the same as a nonliving thing in science.<br><br> Fact:<br><br> Evidence:
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I recently did this assignment!

Instructions: Read each myth (untruth). Reword it to make a factual statement. Then, give two to three reasons why the myth is untrue. Use complete sentences and support your answer with evidence, using your own words.  

________________________________________

Answer:

Myth: A dead organism is the same as a nonliving thing in science.

o Fact: In science, dead is the same as nonliving.

o Evidence: Things that are nonliving never had the characteristics of life, and never will. Things that are dead once did have the characteristics of life, but when they die, they lose some of the characteristics. That is why dead and non-living are NOT the same thing.

Hope this helped!

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4 0
3 years ago
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The accepted value for the mass of a moonrock is 46.37 g. In an experiment the rock is measured to be 47.25 g. What is the perce
Artist 52 [7]

Answer:

The answer is

<h2>2.00 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual measurement = 46.37 g

error = 47.25 - 46.37 = 0.88

The percentage error of the measurement is

P(\%) =  \frac{0.88}{46.37}  \times 100 \\  = 1.89777873...

We have the final answer as

<h3>2.00 %</h3>

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Answer:

I believe its True

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