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mars1129 [50]
3 years ago
15

Consider the following types of electromagnetic radiation:

Chemistry
1 answer:
liq [111]3 years ago
6 0

Explanation:

Electromagnetic wave              Wavelength

(1) Microwave  =   1 m to 1 mm = 10^9 nm to 10^6 nm

(2) Ultraviolet  =    10 nm to 400 nm

(3) Radio waves  =   1 mm to 100 km = 10^6 nm to 10^{14}nm

(4) Infrared  =    700 nm to 1 mm

(5) X-ray  =   0.01 nm to 10 nm

(6) Visible =   400 nm t0 700 nm

a) In order of increasing wavelength:

: 5 < 2 < 6 < 4 < 1 < 3

b) Frequency of the electromagnetic wave given as:

\nu=\frac{c}{\lambda }

\nu = frequency

\lambda = Wavelength

c = speed of light

\nu \propto \frac{1}{\lambda }

So, the increasing order of frequency:

: 3 < 1 < 4 < 6 < 2 < 5

c) Energy(E) of the electromagnetic wave is given by Planck's equation :

E=h\nu

E\propto \nu

So, the increasing order of energy:

: 3 < 1 < 4 < 6 < 2 < 5

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kolezko [41]

Answer:

104.56cm³

Explanation:

Mass=826g

Density =7.9g/cm³

Volume =Mass /Density

Volume =826/7.9

Volume =104.56cm³

5 0
1 year ago
How do you write 561983 in scientific notation?
Artist 52 [7]

Answer:

5.61983 × 10^5

Explanation:

Move the decimal forward 5 spaces, each time doing so you add 10^(# of spaces moved, in this case 5)

7 0
2 years ago
Hich sentence most accurately describes electrically charged objects?
Ket [755]

Answer:

They attract or repel other charged objects without touching them.

Explanation:

My chemistry teacher always says like repels like opposite attracts.

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!!
Inga [223]

Answer:

d=1.5\ g/cm^3

Explanation:

Given that,

The mass of the rock, m = 15 g

The volume of the rock, V = 10 cm³

We need to find the density of the rock. The density of an object is equal to the mass per unit volume such that,

d=\dfrac{m}{V}\\\\d=\dfrac{15\ g}{10\ cm^3}\\\\d=1.5\ g/cm^3

So, the density of the rock is equal to 1.5\ g/cm^3.

3 0
3 years ago
Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of ammonium phosphate and nickel(
densk [106]

Answer:

2PO_4^{3-}(aq)+3Ni^{2+}(aq)\rightarrow Ni_3(PO_4)_2(s)

Explanation:

Hello,

In this case, the molecular chemical reaction is:

(NH_4)_3PO_4(aq)+NiBr_2(aq)\rightarrow NH_4Br(aq)+Ni_3(PO_4)_2(s)

Thus, by considering the ionic species we have:

NH_4^+(aq)+2PO_4^{3-}(aq)+3Ni^{2+}(aq)+Br^-(aq)\rightarrow NH_4^+(aq)+Br^-(aq)+Ni_3(PO_4)_2(s)

Wherein the ammonium and bromide ions are spectator ions since nickel (II) phosphate is largely insoluble in water, therefore, the net ionic equation is:

2PO_4^{3-}(aq)+3Ni^{2+}(aq)\rightarrow Ni_3(PO_4)_2(s)

Best regards.

7 0
3 years ago
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