Given data:
Volume of calcite (V) = 15 cm³,
mass of calcite (m) = 40.5 g,
find the
density of calcite (ρ) = ?
density is defined as " it is the amount of matter of an object in a given volume". Simply it is the ratio of matter in an object to its volume. The unit of density is kg/m³ in SI system or g/cm³ in CGS system.
Mathematically,
density ( ρ) = mass/volume
= m/V g/cm³
= 40.5 g/15 cm³
= 2.7 g/cm³
Hence, the density of calcite is <em>2.7 g/cm³ </em>
Answer:
5501 kg/m^3
Explanation:
The value of g at the Earth's surface is
where G is the gravitational constant
M is the Earth's mass
is the Earth's radius
Solving the formula for M, we find the value of the Earth's mass:
The Earth's volume is (approximating the Earth to a perfect sphere)
So, the average density of the Earth is
Explanation:
Density = mass / volume
ρ = 5200 g / 1400 mL
ρ = 3.7 g/mL
The treasure chest has a higher density than water (1 g/mL), so it sinks.
I beleve it is 15 if not sorry
<h3>
Answer:</h3>
0.82 m/s²
<h3>
How?</h3>
Though its gravity is weak compared to earth, Eris has the strongest gravity out of all the dwarf planets: 0.82 m/s².
<h3>
How Is Eris Important?</h3>
Eris is the <u>largest</u> dwarf planet in the Solar System, and the <u>ninth largest body orbiting our Sun.</u> The discovery of Eris was so important because it was a celestial body larger than Pluto, which forced astronomers to consider, for the first time in history, what the definition of a planet truly is!
Hope this helps you!! :D
