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elena55 [62]
2 years ago
13

The mass of the car?

Physics
2 answers:
iogann1982 [59]2 years ago
6 0
The mass of a car is 1050kg i did this
Nonamiya [84]2 years ago
3 0

Answer:

1050 kg

Explanation:

The formula for kinetic energy is:

KE (kinetic energy) = 1/2 × m × v² where <em>m</em> is the <em>mass in kg </em>and <em>v</em> is the velocity or <em>speed</em> of the object <em>in m/s</em>.

We can now substitute the values we know into this equation.

KE = 472 500 J and v = 30 m/s:

472 500 = 1/2 × m × 30²

Next, we can rearrange the equation to make m the subject and solve for m:

m = 472 500 ÷ (1/2 × 30²)

m = 472 500 ÷ 450

m = 1050 kg

Hope this helps!

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Which of the following would not be considered a projectile?
Naddika [18.5K]

Answer:

e. All of the above are projectile

Explanation:

A projectile is an object with motion, aka a non-zero speed. A cannonball throwing straight up, rolling down a slope, rolling off the edge of a tale, thrown through the air have motion. They all have speed and kinetic energy. Therefore they can all be considered a projectile.

5 0
3 years ago
What is the potential difference across a parallel-plate capacitor whose plates are separated by a distance of 4.0 mm where each
suter [353]

The potential difference across the parallel plate capacitor is 2.26 millivolts

<h3>Capacitance of a parallel plate capacitor</h3>

The capacitance of the parallel plate capacitor is given by C = ε₀A/d where

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  • A = area of plates and
  • d = distance between plates = 4.0 mm = 4.0 × 10⁻³ m.

<h3>Charge on plates</h3>

Also, the surface charge on the capacitor Q = σA where

  • σ = charge density = 5.0 pC/m² = 5.0 × 10⁻¹² C/m² and
  • a = area of plates.

<h3>The potential difference across the parallel plate capacitor</h3>

The potential difference across the parallel plate capacitor is V = Q/C

= σA ÷ ε₀A/d

= σd/ε₀

Substituting the values of the variables into the equation, we have

V = σd/ε₀

V = 5.0 × 10⁻¹² C/m² × 4.0 × 10⁻³ m/8.854 × 10⁻¹² F/m

V = 20.0 C/m × 10⁻³/8.854 F/m

V = 2.26 × 10⁻³ Volts

V = 2.26 millivolts

So, the potential difference across the parallel plate capacitor is 2.26 millivolts

Learn more about potential difference across parallel plate capacitor here:

brainly.com/question/12993474

7 0
3 years ago
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Answer:

Q = - 256 X 10⁻⁷ C .

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E = k Q /d² Where k is a constant and it is equal to 9 x 10⁹

Put the given value in the equation

9 x 10² = \frac{9\times10^9\times Q}{(14+2)^2\times10^{-4}}

Q = \frac{9\times16^2\times10^{-2}}{9\times10^9}

Q = - 256 X 10⁻⁷ C .

It will be negative in nature as the field is directed towards the center.

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serg [7]

Explanation:

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In the context, it is seen that there is a point in the distance - time graph. And the values of the point in the graph is (4,15).

Now here, the distance is plotted in the  ordinate or the vertical y-axis while time is plotted in the abscissa or the horizontal x-axis.

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Explanation:

<h2>the expression of x= -4t+2t^2 where x is displecement?</h2>
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