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scoray [572]
3 years ago
13

How can the time period of a pendulum be decreased or increased

Physics
1 answer:
erastovalidia [21]3 years ago
5 0

Explanation:

The period of a simple pendulum is:

T = 2π √(L/g)

where L is the length of the pendulum and g is the acceleration due to gravity.

The period of a pendulum can be decreased by decreasing the length of the pendulum or by moving the pendulum to a place with a higher gravity.

The period of a pendulum can be increased by increasing the length of the pendulum or by moving the pendulum to a place with a lower gravity.

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What is the kinetic energy in joules of a 0.05. kg bullet traveling 310 m/s
Wittaler [7]
The formula is=1/2(m x v^2)

so = 1/2*(0.05)*(310)^2

ans is =2402.5 joules
3 0
3 years ago
6th grade science !!!!!!!!!!!!!!!​
posledela

Answer:

71

Explanation:

5 0
3 years ago
A testable question about what would happen if you fell into a black hole
daser333 [38]

Answer:

You wouldnt fall you would be sucked and you would lose all air supply and you lungs would pop

Explanation:

7 0
2 years ago
Find the direction and magnitude of Ftot, the total force exerted on her by the others, given that the magnitudes F1 and F2 are
Mars2501 [29]

Answer:

 θ = 36°

Explanation:

given,

F₁ = 22.8 N

F₂ = 16.6 N

magnitude of force = ?

direction of force = ?

F = \sqrt{F_1^2 + F_2^2}

F = \sqrt{22.8^2 + 16.6^2}

F = \sqrt{795.4}

      F = 28.20 N

direction

\theta = tan^{-1}(\dfrac{F_2}{F_1})

\theta = tan^{-1}(\dfrac{16.6}{22.8})

\theta = tan^{-1}(0.728)

       θ = 36°

5 0
3 years ago
An 800-kHz radio signal is detected at a point 2.7 km distant from a transmitter tower. The electric field amplitude of the sign
dimaraw [331]

Answer:

Option D is correct: 170 µW/m²

Explanation:

Given that,

Frequency f = 800kHz

Distance d = 2.7km = 2700m

Electric field Eo = 0.36V/m

Intensity of radio signal

The intensity of radial signal is given as

I = c•εo•Eo²/2

Where c is speed of light

c = 3×10^8m/s

εo = 8.85 × 10^-12 C²/Nm²

I = 3×10^8 × 8.85×10^-12 × 0.36²/2

I = 1.72 × 10^-4W/m²

I = 172 × 10^-6 W/m²

I = 172 µW/m²

Then, the intensity of the radio wave at that point is approximately 170 µW/m²

7 0
2 years ago
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