Answer:
Increasing its charge
Increasing the field strength
Explanation:
For a charged particle moving in a circular path in a uniform magnetic field, the centripetal force is provided by the magnetic force, so we can write:

where
q is the charge
v is the velocity
B is the magnetic field
m is the mass
r is the radius of the orbit
The period of the motion is

Re-arranging for r

And substituting into the previous equation

Solving for T,

So we see that the period is:
- proportional to the charge and the magnetic field
- inversely proportional to the mass and the square of the speed
So the following will increase the period of the particle's motion:
Increasing its charge
Increasing the field strength
Answer:
The magnitude of the force is 12 N Upwards
Explanation:
The force on a positive charge will be in the same direction as the field, but the force on a negative charge will be in the opposite direction to the field. Thus the direction of the force is upward.
Given;
magnitude of charge, q = 0.06 C
magnitude of electric field, E = 200 N/C
The magnitude of the force is given by;
F = qE
F = 0.06 x 200 N/C
F = 12 N Upwards
Therefore, the magnitude of the force is 12 N Upwards
I would believe that this is false.