I dont see it ;-; REEEEEEEE
H atoms=4
S=2
O=8
Bcz it H2SO4 is multiplied with 2 therefore no. Of atoms will be multiplied by 2
Okay first you have to recognize that the maximum Gravitational potential energy will equal the maximum kinetic energy. The maximum GPE will equal when the stone is at its highest point and the max KE will be right before the stone hits the ground. So
GPE max = KE max
mgh = 1/2mv^2
Mass cancels as it is on both sides
gh = 1/2v^2
Multiply by 2
2gh = v^2
Square root
v = √2gh
Now plug in
v = √2(9.8)(4)
v = 8.85 m/s
Now use the mass to calculate the momentum just before it hits the ground as this is the speed right before it hits the ground
p = mv
p = (3)(8.85)
p = 26.55 kgm/s
Answer:
85.14 m
Explanation:
Let g = 9.81 m/s2. We can find the truck mass from its weight
m = W/g = 14000 / 9.81 = 1427 kg
So if the maximum friction could be the truck weight, which is F = 14000N, then that would also be the maximum centripetal force it could be. According to Newton 2nd law of motion, the maximum centripetal acceleration the truck can have when traveling at a curve is
a = F / m = 14000 / 1427 = 9.81 m/s2
By applying the following formula we can find the minimum safe radius R of the curve when traveling at speed of 28.9 m/s

