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Tema [17]
3 years ago
12

8. If horizontal velocity is 5 m/s, and vertical velocity is 8 m/s, what is the

Physics
1 answer:
zhenek [66]3 years ago
7 0

Answer:

9.4

Explanation:

magnitude is the sum of the squares.

\sqrt{5^2+8^2} =9.4339\\

If you are given horizontal and vertical components, treat those as the rise and run of a triangle, the rise of 8 with a run of 5 and you want to find the hypotenuse.

How do you find the long side of a triangle?  

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qwelly [4]
It's about 6 cm long
6 0
3 years ago
3. In 1989, Michel Menin of France walked on a tightrope suspended under a
Tamiku [17]

Answer: 80m

Explanation:

Distance of balloon to the ground is 3150m

Let the distance of Menin's pocket to the ground be x

Let the distance between Menin's pocket to the balloon be y

Hence, x=3150-y------1

Using the equation of motion,

V^2= U^s + 2gs--------2

U= initial speed is 0m/s

g is replaced with a since the acceleration is under gravity (g) and not straight line (a), hence g is taken as 10m/s

40m/s is contant since U (the coin is at rest is 0) hence V =40m/s

Slotting our values into equation 2

40^2= 0^2 + 2 * 10* (3150-y)

1600 = 0 + 63000 - 20y

1600 - 63000 = - 20y

-61400 = - 20y minus cancel out minus on both sides of the equation

61400 = 20y

Hence y = 61400/20

3070m

Hence, recall equation 1

x = 3150 - 3070

80m

I hope this solve the problem.

6 0
3 years ago
A pendulum Bob released from some initial height such that the speed of the bob at the bottom of the swing is 1.9m/s. What is th
Dmitriy789 [7]

Answer:

h = 18.4 cm

Explanation:

Given that,

The speed of the bob at the bottom of the swing is 1.9m/s.

We need to find the initial height of the bob. Let it is h.

We can find it using the conservation of energy i.e.

mgh=\dfrac{1}{2}mv^2

Where

v is speed of the bob

So,

h=\dfrac{v^2}{2g}\\\\h=\dfrac{(1.9)^2}{2\times 9.8}\\\\h= 0.184\ m

or

h = 18.4 cm

So, the initial height of the bob is 18.4 cm.

8 0
2 years ago
Describe the location of point a. explain what you used as a reference point for you your location
Gwar [14]
I used rise and run to see where point a lies .
That's kind of an answer you could you right?
3 0
3 years ago
How much net force is needed to accelerate a 20kg mass at 2.5 m/s2?
Ksenya-84 [330]

Answer:

\boxed{Force \: needed = 50 \: N}

Given:

Mass = 20 kg

Acceleration = 2.5 m/s²

Explanation:

Force = mass × acceleration

= 20 × 2.5

= 50 kg m/s² or 50 N

8 0
3 years ago
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