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3 years ago

8. If horizontal velocity is 5 m/s, and vertical velocity is 8 m/s, what is the

Physics

1 answer:

zhenek [66]3 years ago

7 0

Answer:

9.4

Explanation:

magnitude is the sum of the squares.

$\sqrt{5^2+8^2} =9.4339\\$

If you are given horizontal and vertical components, treat those as the rise and run of a triangle, the rise of 8 with a run of 5 and you want to find the hypotenuse.

How do you find the long side of a triangle?

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2 years ago

In 2H2SO4, the number of hydrogen atoms is , the number of sulfur atoms is , and the number of oxygen atoms is . NextReset

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2 years ago

A 3 kg stone is dropped from a height of 4 m what is its momentum as it strikes the ground

Vitek1552 [10]

Okay first you have to recognize that the maximum Gravitational potential energy will equal the maximum kinetic energy. The maximum GPE will equal when the stone is at its highest point and the max KE will be right before the stone hits the ground. So

GPE max = KE max

mgh = 1/2mv^2

Mass cancels as it is on both sides

gh = 1/2v^2

Multiply by 2

2gh = v^2

Square root

v = √2gh

Now plug in

v = √2(9.8)(4)

v = 8.85 m/s

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7 0

2 years ago

5. If x = 0.6 and y = 5, the value of 2(xy)^3 is...

taurus [48]

Explanation:

=2(0.6 * 5)³

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2 years ago

Read 2 more answers

A pick-up truck with two passengers weighs about 14000 N. In good driving conditions around a curve, the maximum friction with t

Zolol [24]

Answer:

85.14 m

Explanation:

Let g = 9.81 m/s2. We can find the truck mass from its weight

m = W/g = 14000 / 9.81 = 1427 kg

So if the maximum friction could be the truck weight, which is F = 14000N, then that would also be the maximum centripetal force it could be. According to Newton 2nd law of motion, the maximum centripetal acceleration the truck can have when traveling at a curve is

a = F / m = 14000 / 1427 = 9.81 m/s2

By applying the following formula we can find the minimum safe radius R of the curve when traveling at speed of 28.9 m/s

$a = \frac{v^2}{R}$

$R = \frac{v^2}{a} = \frac{28.9^2}{9.81} = 85.14 m$

6 0

3 years ago