(See picture) may I have help!!?
1 answer:
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1) 1.2 m/s
First of all, we need to find the angular velocity of the blade at time t = 0.200 s. This is given by
where
is the initial angular velocity
is the angular acceleration
Substituting t = 0.200 s, we find
Let's now convert it into rad/s:
The distance of a point on the tip of the blade is equal to the radius of the blade, so half the diameter:
And so now we can find the tangential speed at t = 0.200 s:
2)
The tangential acceleration of a point rotating at a distance r from the centre of the circle is
where is the angular acceleration.
First of all, we need to convert the angular acceleration into rad/s^2:
A point on the tip of the blade has a distance of
r = 0.400 m
From the centre; so, the tangential acceleration is
3)
The centripetal acceleration is given by
where
v is the tangential speed
r is the distance from the centre of the circle
We already calculate the tangential speed at point a):
v = 1.2 m/s
while the distance of a point at the end of the blade from the centre is
r = 0.400 m
Therefore, the centripetal acceleration is
Case d) has the strongest gravitational force
Explanation:
The magnitude of the gravitational force between two objects is given by the equation:
where :
is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between the objects
a) For this pair of objects:
m1 = 10 kg
m2 = 2 kg
r = 30 km = 30,000 m
So the gravitational force is
b) For this pair of objects:
m1 = 10 kg
m2 = 10 kg
r = 30 km = 30,000 m
So the gravitational force is
c) For this pair of objects:
m1 = 2 kg
m2 = 2 kg
r = 10 km = 10,000 m
So the gravitational force is
d) For this pair of objects:
m1 = 10 kg
m2 = 10 kg
r = 10 km = 10,000 m
So the gravitational force is
Therefore, the strongest gravitational force is in case d).
Learn more about gravitational force:
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