Their velocity afterward is v=3.467 m/s
Explanation:
Given:
Mass of the first football player= 91.5 kg
Initial velocity of the football player 3.73 m/s
Mass of second football player=63.56 kg
Initial velocity of the second football player=3.09 m/s
To find:
Final velocity of both players=?
Solution:
According to the law of conservation of momentum,
Initial momentum =final momentum
mathematically represented as
...........................(1)
where
=intial velocity of the football player
= inital velocity of second football player
=finall velocity of the first football player
=final velocity of second football player
after tackling , both the football players moves with the same velocity,
so ![v_1=v_2=v](https://tex.z-dn.net/?f=v_1%3Dv_2%3Dv)
Hence equation (1) becomes
![m_1u_1+m_2u_2=(m_1+m_2)v](https://tex.z-dn.net/?f=m_1u_1%2Bm_2u_2%3D%28m_1%2Bm_2%29v)
![v=\frac{m_1u_1+m_2u_2}{(m_1+m_2)}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bm_1u_1%2Bm_2u_2%7D%7B%28m_1%2Bm_2%29%7D)
now substituting the values,
![v=\frac{(91.5\times+3.73)+(63.5\times3.09)}{(91.5+63.5)}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B%2891.5%5Ctimes%2B3.73%29%2B%2863.5%5Ctimes3.09%29%7D%7B%2891.5%2B63.5%29%7D)
![v=\frac{(341.29+196.210)}{155}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B%28341.29%2B196.210%29%7D%7B155%7D)
![v=\frac{537.5}{155}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B537.5%7D%7B155%7D)
v=3.467 m/s