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Zina [86]
3 years ago
12

How does the electric potential energy change as the electron moves from i to f?

Physics
1 answer:
Flura [38]3 years ago
3 0

Answer: it increases

Explanation: .

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TRUE OR FALSE, I would be so happy pzl help0 me
Darina [25.2K]

sorry but i only know of 7 and 8 and the both are true

6 0
3 years ago
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A chicken flaps off the roof of the henhouse with a velocity of 4.5 m/s north. The chicken lands 2.8 seconds later. If a hungry
katrin2010 [14]
I think that it might be B?
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8 0
3 years ago
What are things measured by mass
Free_Kalibri [48]
Anything that is possibly solid or can be contained in a solid

Mass is the amount of matter that is contained in a certain object.
Like
20 kg
10 g
100 lb
6 0
3 years ago
We would like to use the relation V(t)=I(t)RV(t)=I(t)R to find the voltage and current in the circuit as functions of time. To d
drek231 [11]

Answer:

V = -RC (dV/dt)

Solving the differential equation,

V(t) = V₀ e⁻ᵏᵗ

where k = RC

Explanation:

V(t) = I(t) × R

The Current through the capacitor is given as the time rate of change of charge on the capacitor.

I(t) = -dQ/dt

But, the charge on a capacitor is given as

Q = CV

(dQ/dt) = (d/dt) (CV)

Since C is constant,

(dQ/dt) = (CdV/dt)

V(t) = I(t) × R

V(t) = -(CdV/dt) × R

V = -RC (dV/dt)

(dV/dt) = -(RC/V)

(dV/V) = -RC dt

∫ (dV/V) = ∫ -RC dt

Let k = RC

∫ (dV/V) = ∫ -k dt

Integrating the the left hand side from V₀ (the initial voltage of the capacitor) to V (the voltage of the resistor at any time) and the right hand side from 0 to t.

In V - In V₀ = -kt

In(V/V₀) = - kt

(V/V₀) = e⁻ᵏᵗ

V = V₀ e⁻ᵏᵗ

V(t) = V₀ e⁻ᵏᵗ

Hope this Helps!!!

5 0
4 years ago
The equations below show the total amount of water in gallons, y, that has flowed through two different types of shower heads af
Dennis_Churaev [7]

Answer:

The correct option is option (B)

Explanation:

Given that,

The equation below show the total amount of water in gallons, y that has flowed through two different types of showers heads after x minute.

Type A: y =1.25 x

Type B: y= 2.50 x

So,

The amount of water per minute is =\frac{\textrm{The amount of water}}{\textrm{Time}}

For type A

y =1.25 x

\Rightarrow \frac{y}{x}=1.25

For type B

y =2.50 x

\Rightarrow \frac{y}{x}=2.50

\Rightarrow \frac{y}{x}=2\times 1.25

The amount of  water flowed through Type B is twice that flowed trough type A per minute.

4 0
3 years ago
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