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melomori [17]
2 years ago
10

when methane reacts with oxygen, the products are carbon dioxide and water. How many grams of carbon dilxide are formed if 30 g

of methane react completely with 75 g of oxygen to form 50 g of water?
Chemistry
1 answer:
Wittaler [7]2 years ago
4 0

Answer:

CH4+2O2→CO2+2H2O

Moles of oxygen=3232=1

Moles of carbon dioxide=4422=0.5

Moles of water=1818=1

1 mole of methane reacts with 2 moles of oxygen to give 1 mole of CO2 and 2 moles of water so 0.5 mole of methane will be required which is equal to 0.5×16=8g.

Explanation:

8g

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Consider the reaction: 2BrF3(g) --> Br2(g) + 3F2(g)
riadik2000 [5.3K]

Answer : The entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition is 217.68 J/K

Explanation :

The given balanced reaction is,

2BrF_3(g)\rightarrow Br_2(g)+3F_2(g)

The expression used for entropy change of reaction (\Delta S^o) is:

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{Br_2}\times \Delta S_f^0_{(Br_2)}+n_{F_2}\times \Delta S_f^0_{(F_2)}]-[n_{BrF_3}\times \Delta S_f^0_{(BrF_3)}]

where,

\Delta S^o = entropy change of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

\Delta S_f^0_{(Br_2)} = 245.463 J/mol.K

\Delta S_f^0_{(F_2)} = 202.78 J/mol.K

\Delta S_f^0_{(BrF_3)} = 292.53 J/mol.K

Now put all the given values in this expression, we get:

\Delta S^o=[1mole\times (245.463J/K.mole)+3mole\times (202.78J/K.mole)}]-[2mole\times (292.53J/K.mole)]

\Delta S^o=268.74J/K

Now we have to calculate the entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition.

From the reaction we conclude that,

As, 2 moles of BrF_3 has entropy change = 268.74 J/K

So, 1.62 moles of BrF_3 has entropy change = \frac{1.62}{2}\times 268.74=217.68J/K

Therefore, the entropy change of reaction for 1.62 moles of BrF_3 reacts at standard condition is 217.68 J/K

3 0
4 years ago
Metals react with oxygen to give oxides with the general formula MxOy. What is a balanced chemical equation for the reaction of
katovenus [111]

Answer: 4Fe+3O_2\rightarrow 2Fe_2O_3

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

Here iron is having an oxidation state of +3 called as Fe^{3+} cation and oxide O^{2-} is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Fe_2O_3.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

2Fe+3O_2\rightarrow 2Fe_2O_3

8 0
3 years ago
Read 2 more answers
What is the result of adding 2.5 × 10³ and 3.5 × 10²?
Elanso [62]

Answer:

A

Explanation:

It is correct please I hope it helps! :)

7 0
3 years ago
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An unknown gas diffuses 1.25 times faster than CO2 gas. What is the molar mass of the unknown gas?​
hodyreva [135]

Answer:

28.16 g/mol

Explanation:

From Graham's law;

Let the rate of diffusion of gas X be 1.25

Let the rate of diffusion of CO2 be 1

Molecular mass of gas X= M

Molecular mass of CO2 = 44g/mol

1.25/1=√44/M

(1.25/1)^2 = 44/M

1.5625 = 44/M

M= 44/1.5625

M= 28.16 g/mol

4 0
3 years ago
Explain what keeps the electrons confined in the space surrounding the nuleus
aleksklad [387]

Answer:

Electrons are trapped inside the atom because of the attraction forces with positively charged protons that are found in the nucleus.

7 0
3 years ago
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