Answer: This image is the answer to this question.
Explanation:
5.6 Al(OH)3
5.6 Al, 16.8 O, 16.8 H
16.8 mols of oxegyn in 5.6 mols of Al(OH)3
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Answer:
1.75M
Explanation:
molarity = number of moles of solute/ number of L of solution =
=0.35 mol/0.2L = 1.75 mol/L = 1.75 M
it will be hard, but you can do it. Just study given the materials for the course. Understand enthalpy and entropy, and various types of bonding and you'll be fine.
