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1 answer:
This question involves the concepts of induced emf and magnetic field.
The wire has to move at a speed of "20 m/s".
<h3>Speed of Wire</h3>The emf induced in a current carrying conductor when it passes through a magnetic field is given by the following formula:
where,
- v = speed = ?
- E = induced emf = 10 volts
- B = magnetic field = 2.5 T
- l = length of wire = 0.2 m
Therefore,
v = 20 m/s
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Answer:
(a) W=1.20×10⁴J
(b) U= -5.46×10⁴J
(c) Q= -4.26×10⁴J
Explanation:
Given that student does 1.20×10⁴J work
(a) W=1.20×10⁴J
Work done by student,so positive sign
During the process, his internal energy decreases by 5.46×10⁴J.
(b) U= -5.46×10⁴J.
As the Energy decreases therefore negative sign
For (c) Q
We know the formula