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3 years ago

Need an answer, please need an answer, please

Physics

1 answer:

Karolina [17]3 years ago

6 0

9514 1404 393

Answer:

moderate low: 82
moderate high: 112.75
vigorous low: 123
vigorous high: 174.25

Explanation:

When calculations are repetitive, I find it convenient to use a calculator that can work with tables.

The PMHR is (220 -15) = 205.

Each of the other heart rates is computed as the formula shows. For example, the low moderate heart rate is 205×0.40 = 82 bpm

The other rates are shown in the attached table. They are computed the same way.

You might be interested in

Which forms of energy are involved when you turn on a desk lamp and the bulb becomes hot?

alukav5142 [94]

Answer:

Electric energy moves through the wire to the lamp's bulb. In the bulb, electric energy transforms into thermal energy and light energy.

Explanation:

4 0

3 years ago

In a double-slit experiment, if the central diffraction peak contains 13 interference fringes, how many fringes are contained wi

Ronch [10]

Answer:

Explanation:

Width of central diffraction peak is given by the following expression

Width of central diffraction peak= 2 λ D/ d₁

where d₁ is width of slit and D is screen distance and λ is wave length.

Width of other fringes become half , that is each of secondary diffraction fringe is equal to

λ D/ d₁

Width of central interference peak is given by the following expression

Width of each of bright fringe = λ D/ d₂

where d₂ is width of slit and D is screen distance and λ is wave length.

Now given that the central diffraction peak contains 13 interference fringes

so ( 2 λ D/ d₁) / λ D/ d₂ = 13

then ( λ D/ d₁) / λ D/ d₂ = 13 / 2

= 6.5

no of fringes contained within each secondary diffraction peak = 6.5

6 0

3 years ago

An 877 kg drag race car accelerates from rest to 116 km/h in 0.951 s. What change in momentum does the force produce? Answer in

Eduardwww [97]

Answer:

The change in momentum is 28265.71 kg-m/s.

Explanation:

Given that,

Mass of a car, m = 877 kg

Initial velocity of the car, u = 0 (at rest)

Final velocity of the car, v = 116 km/h = 32.23 m/s

Time, t = 0.951 s

We need to find the change in momentum produced by the force. It can be calculated as the difference of final momentum and the initial momentum.

$\Delta P=m(v-u)\\\\=877\times (32.23-0)\\\\=28265.71\ kg-m/s$

So, the change in momentum is 28265.71 kg-m/s.

7 0

2 years ago

At a particular instant, a moving body has a kinetic energy of 295 J and a momentum of magnitude 25.1 kg · m/s.(a)What is the sp

motikmotik

Answer:

a) 23.51 m/s

b) 1.07 kg

Explanation:

Parameters given:

Kinetic energy, K = 295 J

Momentum, p = 25.1 kgm/s

a) The kinetic energy of a body is given as:

$K = \frac{1}{2} mv^2$

where m = mass of the body and v = speed of the body

We know that momentum is given as:

p = mv

Therefore:

K = 1/2 * pv

=> v = 2K / p

v = (2 * 295) / 25.1 = 23.51 m/s

The velocity of the body at that instant is 23.51 m/s.

b) Momentum is given as:

p = mv

=> m = p / v

m = 25.1 / 23.51 = 1.07 kg

The mass of the body at that instant is 1.07 kg

5 0

3 years ago

suppose 384g of steam originally at 100C is quickly cooled to produce liquid water at 31C. How much heat must be removed from th

dlinn [17]

Answer:

$Q=977216.256\ J=977.216\ kJ$

Explanation:

Given:

mass of steam, $m=384\ g$

temperature of steam, $T_{is}=100^{\circ}C$

temperature of resultant water, $T_{fw}=31^{\circ}C$

We have,

latent heat of vapourization of water, $L=2256\ J.g^{-1}$

specific heat capacity of water, $c=4.186\ J.g^{-1}$

When we cool the steam of 100°C then firstly it loses its latent heat to convert into water of 100°C and the further cools the water.

Now the heat removed from steam to achieve the final state of water:

$\rm Q=latent\ heat\ of\ vapourization+sensible\ heat\ of\ water$

$Q=m(L+c.\Delta T)$

$Q=384(2256+4.186\times (100-31))$

$Q=977216.256\ J=977.216\ kJ$

3 0

3 years ago

Need an answer, please need an answer, please​

Need an answer, please need an answer, please