Answer:
The position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be
1) Position: Behind the mirror
2) Nature: Virtual
3) Size: Smaller than the object
Explanation:
Due to the nature and use of rear view mirrors, which are meant to enable the front facing driver visualize a wide area of the back portion of the vehicle, such that the images of the object will always remain smaller than the object, require a convex image
The image size, location, nature and orientation of an object placed in front of a convex mirror is diminished, behind the mirror of the upright, virtual, and upright
Therefore, the position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be
Position: Behind the mirror
Nature: Virtual
Size: Smaller than the object.
Vector A is of magnitude 12 m and it makes an angle of 37 degree with Y axis
So here we can say that
Similarly we have
So here we have
option A is correct
Answer:
a = 0.098 m/s²
Explanation:
The satellite, at any distance from the center of the Earth, is subject to the attractive force due to the Earth, according to the Newton´s Universal Law of gravitation, as follows:
Fg = G*ms*mE / (rse)²
According to Newton´s 2nd Law, neglecting any other force acted upon the satellite, we can write the following equation:
Fg = ms*a = G*ms*mE / (rse)²
⇒ a = G*mE / (rse)² (1)
As the distance between the satellite and the center of the Earth is 10 times the radius of the Earth, replacing this value in (1), we have:
a = G*mE / (10*RE)² = G*mE/(RE)² * (1/100)
but G*mE/(RE)², is just g, the acceleration due to gravity on the surface of the earth, so the gravitational acceleration due to Earth at satellite A, is as follows:
a = g*(1/100) = 0.01*g = 0.098 m/s²
Answer:
Wavelength of sound in the pipe is 6.0 m
Explanation:
As we know that closed pipe is given to us so here at open end it will form antinode while at closed end it will form Node
Here we know that in closed pipes on odd harmonics will exist
so here for third harmonic we have
where L = length of the pipe
so we have
Answer:t=0.54 s
Explanation:
Given
Jacob is traveling 5 m/s in North direction
Jacob throw a ball with a in south direction with a velocity of 5 m/s
Ball is thrown in opposite direction of motion of car therefore it seems as if it is dropped from car as its net horizontal velocity is 5-5=0
Time taken by ball to reach ground
t=0.54 s
Motion of ball will be straight line
