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Alona [7]
3 years ago
14

A small truck has gone over an embankment. The driver has a head injury and is​ confused, but is able to tell you that he is hau

ling​ N-acetyl-para-aminophenol. Which resource would provide you with the best initial information about this​ chemical?
Physics
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer:

"Emergency resource guidebook" would provide you with the best initial information about this​ chemical

Explanation:

This guidebook is for the first responders in case of the beginning of any dangerous goods or the hazardous materials transportation incident. It is used in firefighters, paramedics and for the police officers, in countries like Canada, Mexico and also in the United states when responding to these accident cases becomes delay. The book has different colours in it, for chemicals it will be green colour whereas the blue or the yellow colour shows the toxic inhalation materials. In TIH it has initial isolation distance and protective action distance information against the accident. The white is the host specific.

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Which of the following statements is correct about the force of gravity between two objects? (a)It depends on the shape of the o
morpeh [17]

Answer:

(D) It is stronger when the objects are closer.

Explanation:

Newton's universal law 9f gravitation

8 0
4 years ago
1+5-(-5 - 1) whats the answer​
vladimir2022 [97]

Answer:

12

Explanation:

6 0
3 years ago
Read 2 more answers
In the mobile m1=0.42 kg and m2=0.47 kg. What must the unknown distance to the nearest tenth of a cm be if the masses are to be
LuckyWell [14K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From he question we are told that

    The first mass is   m_1 = 0.42kg

      The second mass is  m_2 = 0.47kg

From the question we can see that at equilibrium the moment about the point where the  string  holding the bar (where m_1 \ and \ m_2 are hanged ) is attached is zero  

   Therefore we can say that

               m_1 * 15cm  = m_2 * xcm

Making x the subject of the formula  

                x = \frac{m_1 * 15}{m_2}

                    = \frac{0.42 * 15}{0.47}

                     x = 13.4 cm

Looking at the diagram we can see that the tension T  on the string holding the bar where m_1  \  and   \ m_2 are hanged  is as a result of the masses (m_1 + m_2)

     Also at equilibrium the moment about the point where the string holding the bar (where (m_1 +m_2)  and  m_3 are hanged ) is attached is  zero

   So basically

          (m_1 + m_2 ) * 20  = m_3 * 30

          (0.42 + 0.47)  * 20 = 30 * m_3

 Making m_3 subject

          m_3 = \frac{(0.42 + 0.47) * 20 }{30 }

                m_3 = 0.59 kg

3 0
3 years ago
A ball of moist clay falls 15.0 m to the ground. It is in contact with the ground for 20.0 ms before stopping. (a) What is the m
rosijanka [135]

Answer:

a= -0.86 m/s²

The negative sign shows that ball down the ground or moving down

Explanation:

Vf² - Vo² = 2gS

where

Vf = velocity of clay as it hits the ground

Vo = initial velocity of clay = 0

g = acceleration due to gravity = 9.8 m/sec^2 (constant)

S = distance travelled by clay = 15 m

Substituting appropriate values,

Vf² - 0 = 2(9.8)(15)  

Vf = 17.15 m/sec.

Formula to use is,  

V - Vf = aT

where

V = velocity of clay when it stops = 0

Vf = 17.15 m/sec (as determined above)

a = acceleration

T = 20 ms  

Put the values to find acceleration

a=(V-Vf)/T

a=(0-17.15)/20

a= -0.86 m/s²

The negative sign shows that ball down the ground

3 0
4 years ago
What are the four system of measurement ​
Rudiy27

Answer:

ask google

Explanation:

5 0
4 years ago
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