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3 years ago

Improvements in which area would help reduce the possibility of damage to the environment when using uranium as a fuel?

Chemistry

1 answer:

kogti [31]3 years ago

5 0

Answer:

A is the answer; 'more-efficient extraction techniques

Explanation:

I just took the test and got it right :D

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Use the image to answer the question.

Lena [83]

Answer:

1. the process of plants taking in sunlight and creating oxygen

2. outputs are oxygen

3. inputs are sunlight

Explanation:

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3 years ago

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how does a jellyfish reproduce?explain the process and use the words polyp and medusa. hint my there are two stages of reproduct

Mazyrski [523]

Jellyfish reproduction involves several different stages. In the adult, or medusa, stage of a jellyfish, they can reproducesexually by releasing sperm and eggs into the water, forming a planula. ... During this stage, which can last for several months or years, asexual reproduction occurs.

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3 years ago

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What is heat

Nimfa-mama [501]

Answer:

energy that freely moves from one place to another. It is responsible for vibration of particles of matter

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3 years ago

Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh

Dima020 [189]

Answer: The $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

Explanation:

For the given chemical reaction:

$2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)$

Half reactions for the given cell follows:

Oxidation half reaction: $ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V$ ( × 2)

Reduction half reaction: $Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=1.36-(0.954)=0.406V$

To calculate standard Gibbs free energy, we use the equation:

$\Delta G^o=-nFE^o_{cell}$

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

$E^o_{cell}$ = standard cell potential = 0.406 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J$

Hence, the $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

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3 years ago

1. define speed

Harrizon [31]

1- thé everyday use of kinematic basically the speed for something it’s the magnitude.

2-the speed of something in a certain direction
2a- They are both related by speed.

3-the capacity of a vehicle which gains speed in a short time

4-it’s an attraction of all matter (not sure on this one)

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3 years ago