The new pressure, P₂ is 6000 atm.
<h3>Calculation:</h3>
Given,
P₁ = 1.5 atm
V₁ = 40 L = 40,000 mL
V₂ = 10 mL
To calculate,
P₂ =?
Boyle's law is applied here.
According to Boyle's law, at constant temperature, a gas's volume changes inversely with applied pressure.
PV = constant
Therefore,
P₁V₁ = P₂V₂
Put the above values in the equation,
1.5 × 40,000 = P₂ × 10
P₂ = 1.5 × 4000
P₂ = 6000 atm
Therefore, the new pressure, P₂ is 6000 atm.
Learn more about Boyle's law here:
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Given the percentage composition of HC as C → 81.82 % and H → 18.18 %
So the ratio of number if atoms of C and H in its molecule can will be:
C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8
So the Empirical Formula of hydrocarbon is:
C 3 H 8
As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol
Now let Molecular formula of the HC be ( C 3 H 8 ) n
Using molar mass of C and H the molar mass of the HC from its molecular formula is:
( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1
Hence the molecular formula of HC is C 3 H 8
Does that help?
I think it might be A. i am not totally sure though
I think it’s A I’m not 100% sure but I mean it’s worth a try
