18.2L of gas at 95°C and 760 torr is placed in a 15L container at 80 degrees * C ; what is the new pressure ?
1 answer:
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In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.
Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.
For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.
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Answer:
v=2010 inches^3
Explanation:
The volume of a cylinder can be found using:
We know the height is 10, the radius is 8, and we can substitute 3.14 in for pi
v=3.14(8^2)(10)
Solve the exponent first
v=3.14(64)(10)
v=3.14(640)
v=2009.6
To the nearest whole number:
v=2010 inches^3