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3 years ago

How would you calculate the acceleration of an object?

Physics

1 answer:

prohojiy [21]3 years ago

4 0

The right answer is c. You are going to divide by the velocity or speed by time.

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_____ is a device

erastovalidia [21]

Answer:

transformers

Explanation:

A transformer is a device that increases or decreases voltage.

8 0

2 years ago

We have a toy gun with a spring constant of 50 N/m. The spring is compressed by 0.2 m. If you neglect friction and the mass of t

Arisa [49]

Answer:

$31.6\:\mathrm{m/s}$

Explanation:

The elastic potential energy of a spring is given by $Us=\frac{1}{2}kx^2$ , where $k$ is the spring constant of the spring and $x$ is displacement from point of equilibrium.

When released, this potential energy will be converted into kinetic energy. Kinetic energy is given by $KE=\frac{1}{2}mv^2$ , where $m$ is the mass of the object and $v$ is the object's velocity.

Thus, we have:

$Us=KE,\\\frac{1}{2}kx^2=\frac{1}{2}mv^2$

Substituting given values, we get:

$\frac{1}{2}\cdot 50\cdot 0.2^2=\frac{1}{2}\cdot 0.002\cdot v^2,\\v^2=\frac{50\cdot 0.2^2}{0.002},\\v^2=1000,\\v\approx \boxed{31.6\:\mathrm{m/s}}$

4 0

3 years ago

When gasoline is burned in a car engine,_____ energy is converted into _____ energy.

Kisachek [45]

<span>Chemical Energy is converted into Mechanical Energy.

</span>When gasoline is burned in a car engine, chemical energy is converted into mechanical energy.

8 0

4 years ago

Read 2 more answers

A 500 kg sack of coal falls vertically onto a 2000 kg railroad flatcar which was initially moving horizontally at 3 m/s. no exte

Zinaida [17]

Since there are no external forces, including friction, act on the flatcar. after the sack rests on the flatcar, we would assume that momentum is conserved. This means that

total momentum of car before collision = total momentum of car after collision.

Recall,

momentum = mass x velocity

From the information given,

mass of car before collision = 2000

velocity of car before collision = 3

Thus,

total momentum of car before collision = 2000 x 3 = 6000

Also,

mass of sack = 500

mass of car and sack after collision = 500 + 2000 = 2500

velocity after collision = v

momentum after collision = 2500 x v = 2500v

Since momentum is conserved, then

6000 = 2500v

v = 6000/2500

v = 2.4

the speed of the flatcar is 2.4 m/s

6 0

1 year ago

Please help me out if you want brainliest !!!!! ASAP easy

Vinvika [58]

Answer:

Road A = 8 meters Wet

Road B = 2 meters Muddy

Road C = 12 meters Dry

Explanation:

8 0

3 years ago