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2 years ago

What completely ionizes in solution

Chemistry

1 answer:

Nata [24]2 years ago

6 0

Answer:

Strong acids. hope this helps :)

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The formula mass of a compound is the A) sum of the atomic masses of its atoms B) sum of the atomic numbers of its atoms C) prod

Digiron [165]

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7 0

3 years ago

A liquid is placed in an evacuated, sealed flask. When will this closed system reach dynamic equilibrium?

timurjin [86]

The liquid will stop converting into vapor. This process is to balanced the amount of substance of both phases inside the flask.

4 0

3 years ago

Read 2 more answers

Consider the reaction: P(s) + 5/2 Cl2(g)PCl5(g) Write the equilibrium constant for this reaction in terms of the equilibrium con

Pani-rosa [81]

Answer: The equilibrium constant for the overall reaction is $K_a\times K_b$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.

a) $P(s)+\frac{3}{2}Cl_2(g)\rightarrow PCl_3(g)$

$K_a=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}$

b) $PCl_3(g)+Cl_2(g)\rightarrow PCl_5(g)$

$K_b=\frac{[PCl_5]}{[Cl_2]\times [PCl_3]}$

For overall reaction on adding a and b we get c

c) $P(s)+\frac{5}{2}Cl_2(g)\rightarrow PCl_5(g)$

$K_c=\frac{[PCl_5]}{[Cl_2]^\frac{5}{2}}$

$K_c=K_a\times K_b=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}\times \frac{[PCl_5]}{[Cl_2]\times [PCl_3]}$

The equilibrium constant for the overall reaction is $K_a\times K_b$

4 0

2 years ago

If 3.0 liters of oxygen gas react with excess carbon monoxide at STP, how many liters of carbon dioxide can be produced under th

mr_godi [17]

Answer:

The volume of CO2 produced is 6.0 L (option D)

Explanation:

Step 1: Data given

Volume of oxygen = 3.0 L

Carbon monoxide = CO = in excess

Step 2: The balanced equation

2 CO (g) + O2 (g) → 2 CO2 (g)

Step 3: Calculate moles of O2

1 mol of gas at STP = 22.4 L

3.0 L = 0.134 moles

Step 3: Calculate moles of CO2

For 2 moles CO we need 1 mol of O2 to produce 2 moles of CO2

For 0.134 moles O2 we'll have 2*0.134 = 0.268 moles CO2

Step 4: Calculate volume of CO2

1 mol = 22.4 L

0.268 mol = 22.4 * 0.268 = 6.0 L

The volume of CO2 produced is 6.0 L

8 0

3 years ago

If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP

nydimaria [60]

Answer:

The answer to your question is V2 = 434.7 l

Explanation:

Data

Volume 1 = V1 = 240 l Volume 2 = ?

Temperature 1 = T1 = 479°K Temperature 2 = T2 = 293°K

Pressure 1 = P1 = 300 KPa Pressure 2 = P2 = 101.325 Kpa

Process

1.- Use the combined gas law to solve this problem

P1V1/T1 = P2V2/t2

-Solve for V2

V2 = P1V1T2 / T1P2

2.- Substitution

V2 = (300)(240)(293) / (479)(101.325)

3.- Simplification

V2 = 21096000 / 48534.675

4.- Result

V2 = 434.7 l

6 0

3 years ago