one mole of MgSO4.7H2O weighs 246.4696 g
<span>in that one mole are seven moles of H2O, weighing 126.1036 g </span>
<span>The percentage of water is this calculation: </span>
<span>(126.1036 / 246.4696) * 100 = 51.17</span><span>%
</span>
Answer:
The final concentration of the Randyne in grams per milliliter = 0.011 g/mL
Explanation:
As we know
C1V1 = C2V2
C1 and C2 = concentration of solution 1 and 2 respectively
V1 and V2 = Volume of solution 1 and 2 respectively
Substituting the given values, we get -
mg/mL
The final concentration of the Randyne in grams per milliliter = 0.011 g/mL
<span>the answer:
The net ionic equation,
H3PO4 (aq) + 3 OH− (aq)------- PO4−3 (aq) + 3 H2O (l),
</span> H3PO4 is a strong acid, (presence of hydrogen H)
OH- is a strong base, (presence of OH-)
so the true answer is <span>strong acid-strong base</span>
Answer:
The colour of the solution will change from blue to transparent and copper will be observed as a layer on the Aluminium piece.
Explanation:
The colour of the solution will change from blue to transparent and copper will be observed as a layer on the Aluminium piece.
Answer:
Explanation:
First convert the grams of Calcium Bromide to moles by using the atomic weight. Then use the formula for molarity, which is moles per liter.
CaBr2 = 199.9 g/mol
10/199.9 = 0.05 moles of CaBr2
x = 0.1L or 100mL
