All categories

1 year ago

A long conducting cylindrical pipe has a length L

1 answer:

8 0

The charge distribute on the inner surface with the radius r₁ will be zero,In the region r₁<r<r₂ will also zero. While on the outer surface with radius r₂ will be -q.

<h3>What is Gauss law?</h3>

The total electric flux out of a closed surface is equal to the charge contained divided by the permittivity,

According to Gauss Law. the electric flux in a given area is calculated by multiplying the electric field by the area of the surface projected in a plane perpendicular to the field.

From the Gauss law, it is stated that the field inside the conductor is zero. Charge will lie only on the surface.

(a)The charge distribute on the inner surface with the radius r₁ will be zero.

(b) In the region r₁<r<r₂ will also zero.

(c)The outer surface with radius r₂ charge distribution will be -q.

Hence, the charge distribute on the inner surface with the radius r₁ will be zero,

To learn more about the Gauss law, refer to the link;

brainly.com/question/2854215

#SPJ1

You might be interested in

Check out this app! It's millions of students helping each other get through their schoolwork. https://brainly.app.link/qpzV02Ma

beks73 [17]

Answer:

OK we appreciate your concern.

3 0

2 years ago

Read 2 more answers

The circumference of a circle is 12π meters. find the circle diameter.

Veseljchak [2.6K]

The circumference of a circle is 2*pi*r=C so plugging in numbers we have
12pi= 2*pi*r so solving for r gives 12pi/2pi=r which gives 6=r so the radius of the circle is 6 meters since diameter is just 2*r this gives 2*r =12 meters so
Diameter = 12meters

7 0

2 years ago

A tray filled with ice is removed from the freezer. After a short period of time, the ice begins to melt.

Sav [38]

A: decreases in specific heat capacity

3 0

3 years ago

A monochromatic light beam is incident on a barium target that has a work function of 2.50 \mathrm{eV} . If a potential differen

leva [86]

The wavelength of the light beam required to turn back all the ejected electrons is 497 nm which is option (b).

Work function is a material property defined as the minimum amount of energy required to infinitely remove electrons from the surface of a particular solid.
The potential difference required to support all emitted electrons is called the stopping potential which is given by $v_0=\frac{K.E_m_a_x}{e}$ .....(1)
where $v_0$ is the stopping potential and e is the charge of the electron given by $1.6\times10^-^1^9$ .

It is given that work function (Ф) of monochromatic light is 2.50 eV.

Einstein photoelectric equation is given by:

$K.E_m_a_x=E-\phi$ ....(2)

where K.E(max) is the maximum kinetic energy.

Substituting (1) into (2) , we get

$ev_0=E-\phi\\1.6\times10^{-19} \times1=E-2.50\\E=1.6\times10^{-19}+2.50\\E=2.50eV$

As we know that $E=\frac{hc}{\lambda}$ ....(3)

where Speed of light, $c = 3\times10^8 m/s$ and Planck's constant , $h = 6.63\times 10^-^1^9Js = 4.14\times 10^-^1^5 eVs$

From equation (3) , we get

$\lambda=\frac{hc}{E} \\\\\lambda=\frac{ 4.14\times 10^-^1^5 \times 3 \times10^8}{2.50} \\\\\lambda=\frac{1240\times10^-^9}{2.50} \\\\\lambda=496.8\times10^-^9\\\\\lambda=497nm$

Learn about more einstein photoelectric equation here:

brainly.com/question/11683155

#SPJ4

8 0

1 year ago

Why does the sample on a microscope slide need to be very thin?

ziro4ka [17]

B. so light can shine through it from below.

4 0

3 years ago

Read 2 more answers