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Whitepunk [10]
3 years ago
8

A centrifuge is a common laboratory instrument that separates components of differing densities in solution. This is accomplishe

d by spinning a sample around in a circle with a large angular speed. Suppose that after a centrifuge in a medical laboratory is turned off, it continues to rotate with a constant angular deceleration for 10.0s before coming to rest.
Part A

If its initial angular speed was 3890rpm , what is the magnitude of its angular deceleration? (|?| in revs/s^2 )

Part B

How many revolutions did the centrifuge complete after being turned off?
Physics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

a_r=389\ rev.s^{-2}

n=58350 rev

Explanation:

Given:

time of constant deceleration, t=10\ s

A.

initial angular speed, N_i=3890\ rpm\

<u>Using equation of motion:</u>

N_f=N_i+a_r.t

0=3890+a_r\times 10

a_r=389\ rev.s^{-2}

B.

Using eq. of motion for no. of revolutions, we have:

n=N_i.t+\frac{1}{2} a_r.t^2

n=3890\times 10+0.5\times 389\times 100

n=58350\ rev

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  1. The current in this motor is equal to 17.27 Ampere.
  2. The energy delivered to this motor in 3.00 hours is equal to 22.38 Megajoules.
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<h3>How to determine the current (in A) delivered to the motor?</h3>

Assuming this electric motor is a single-phase motor and it operates by using DC current, its mechanical power output would be given by:

W = ηIV

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First of all, we would determine the power delivered to this motor as follows:

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Read more on energy here: brainly.com/question/15567897

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Complete Question:

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(b) Find the energy delivered to the motor by electrical transmission in 3.00 h of operation.

(c) If the electric company charges $0.110/kWh, what does it cost to run the motor for 3.00 h?

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