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Whitepunk [10]
4 years ago
8

A centrifuge is a common laboratory instrument that separates components of differing densities in solution. This is accomplishe

d by spinning a sample around in a circle with a large angular speed. Suppose that after a centrifuge in a medical laboratory is turned off, it continues to rotate with a constant angular deceleration for 10.0s before coming to rest.
Part A

If its initial angular speed was 3890rpm , what is the magnitude of its angular deceleration? (|?| in revs/s^2 )

Part B

How many revolutions did the centrifuge complete after being turned off?
Physics
1 answer:
melamori03 [73]4 years ago
8 0

Answer:

a_r=389\ rev.s^{-2}

n=58350 rev

Explanation:

Given:

time of constant deceleration, t=10\ s

A.

initial angular speed, N_i=3890\ rpm\

<u>Using equation of motion:</u>

N_f=N_i+a_r.t

0=3890+a_r\times 10

a_r=389\ rev.s^{-2}

B.

Using eq. of motion for no. of revolutions, we have:

n=N_i.t+\frac{1}{2} a_r.t^2

n=3890\times 10+0.5\times 389\times 100

n=58350\ rev

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Carl is eating lunch at his favorite cafe when his friend Isaac calls and says he wants to meet him. Isaac is calling from a cit
Sonbull [250]

Answer:

106.52 minutes

Explanation:

Given:

Initial distance between Carl and Isaac = 175 miles

speed of Isaac = 65 mph

Speed of Carl = 50 mph

Now, the Carl starts after 35 minutes, but the Isaac has already started so the distance covered by Isaac in 35 minutes will be

= \frac{35}{60}\times65

= 37.91 miles

Therefore,

the distance left between Isaac and Carl = 175 - 37.91 = 137.09 miles

Since Isaac and Carl are moving towards each other,

therefore the relative speed between the both = 65 + 50 = 115 mph

Hence, the time taken to meet = \frac{137.09}{115}

or

The time taken to meet = 1.192 hours

or

The time taken = 1.192 × 60 = 71.52 minutes

Therefore the total time Isaac have been travelling = 71.52 + 35

= 106.52 minutes

7 0
3 years ago
If two carts collide, what type of collision will conserve both momentum and kinetic energy?
g100num [7]
The appropriate answer is d. perfectly elastic. When a perfectly elastic collision occurs both momentum and kinetic energy are preserved. Momentum is the mass of an object times its velocity while kinetic energy is the energy that a moving object has due to its motion. In an elastic collision kinetic energy would be converted to some other form of energy. 
8 0
4 years ago
Read 2 more answers
If you are pushing a table with a force of 5 newtons what is the force pushing back on you
Sonbull [250]
The force pushing back to you would be 5 newtons as Newtons 3rd law says that every action force has an opposite but equal reaction force acting upon it (if i remember correctly  ) 
4 0
4 years ago
A roller coaster moves 200 ft horizontally, then rises 135 ft at an angle of 30.0° above the horizontal. Next, it travels 135 f
vekshin1

Answer:

171 ft

Explanation:

The distance to be calculated is AB

AB = AC + BC

AC;  Cos 60 = AC ÷ 135

AC = 135 cos 60 = 67.5 ft

BC; Cos 40 = BC ÷ 135

BC = 135 cos 40 = 103.416 ft

AB = 67.5 + 103.416 = 170.9159998210 ft

Distance between starting point to end point = 171 ft

4 0
3 years ago
A spinning wheel having a mass of 20 kg and a diameter of 0.5 m is positioned to rotate about its vertical axis with a constant
AlekseyPX

Answer:

ωf = 8.8 rad/s

v = 2.2 m/s

Explanation:

We will use the third equation of motion to find the maximum angular velocity of the wheel:

2\alpha \theta = \omega_f^2 -\omega_I^2

where,

α = angular acceleration = 6 rad/s²

θ = angular displacemnt = 1 rev = 2π rad

ωf = max. final angular velocity = ?

ωi = initial angular velocity = 1.5 rad/s

Therefore,

2(6\ rad/s^2)(2\pi\ rad)=\omega_f^2-(1.5\ rad/s)^2\\\omega_f^2=75.4\ rad/s^2+2.25\ rad/s^2\\\omega_f = \sqrt{77.65\ rad/s^2}

<u>ωf = 8.8 rad/s</u>

Now, for linear velocity:

v = rω = (0.25 m)(8.8 rad/s)

<u>v = 2.2 m/s</u>

7 0
3 years ago
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