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Whitepunk [10]
3 years ago
8

A centrifuge is a common laboratory instrument that separates components of differing densities in solution. This is accomplishe

d by spinning a sample around in a circle with a large angular speed. Suppose that after a centrifuge in a medical laboratory is turned off, it continues to rotate with a constant angular deceleration for 10.0s before coming to rest.
Part A

If its initial angular speed was 3890rpm , what is the magnitude of its angular deceleration? (|?| in revs/s^2 )

Part B

How many revolutions did the centrifuge complete after being turned off?
Physics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

a_r=389\ rev.s^{-2}

n=58350 rev

Explanation:

Given:

time of constant deceleration, t=10\ s

A.

initial angular speed, N_i=3890\ rpm\

<u>Using equation of motion:</u>

N_f=N_i+a_r.t

0=3890+a_r\times 10

a_r=389\ rev.s^{-2}

B.

Using eq. of motion for no. of revolutions, we have:

n=N_i.t+\frac{1}{2} a_r.t^2

n=3890\times 10+0.5\times 389\times 100

n=58350\ rev

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The formula is x = 1/2 at^2 and I have managed to fill in the variables as this. d = 1/2 9.81 m/s^2 1^2
Artyom0805 [142]

Right, as you mentioned in the comments, you find d by plugging in the different values of t.

For t=1\,\mathrm s, we have

d=\dfrac12\left(9.81\,\dfrac{\mathrm m}{\mathrm s^2}\right)(1\,\mathrm s)^2

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8 0
3 years ago
A radioactive material has a count rate of 400 per minute. It has a half life of 40 years. How long will it take to decay to a r
cestrela7 [59]

Answer:

160 years.

Explanation:

From the question given above, the following data were obtained:

Initial count rate (Cᵢ) = 400 count/min

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Time (t) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Initial count rate (Cᵢ) = 400 count/min

Final count rate (Cբ) = 25 count/min

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Cբ = 1/2ⁿ × Cᵢ

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