A car increases velocity from 25 m/s to 50 m/s in 5 seconds. What is the acceleration of the car?

А masd Of 500kg a raised to a height of 6m In 30s Find (a) Workdone .

Mazyrski [523]

Answer:

Work done is 882000joule.

power is 29400watt.

Explanation:

given,

Mass(m)=500kg

Acceleration due to gravity(g)=9.8m/s²

Height(h)=6m

Time taken(t)=30s

Workdone=?

Power=?

now,

workdone=force*displaxement

= m*g*h

=500*9.8*6

=8,82,000joule

so, the work done by the man is 8,82,000joule.

then,

power=workdone/time taken

=8,82,000/30

=29,400watt

so, the required power to lift a load is 29,400watt.

5 0

3 years ago

A 4-kg block and a 2-kg block can move on the horizontal frictionless surface. The blocks are accelerated by a+12-N force that p

lozanna [386]

Answer:

$F_n = -4 N$

Explanation:

Net external force that exerted on the block is given as

$F_{net} = (m_1 + m_2) a$

here we know that

$F = 12 N$

$m_1 = 4 kg$

$m_2 = 2 kg$

now we have

$12 = (4 + 2) a$

so we have

$a = 2 m/s^2$

now the force exerted by bigger block on smaller block is given as

$F_n = ma$

$F_n = (2 \times 2)$

$F_n = 4 N$

now we know that two blocks will exert equal and opposite force on each other

so here the force exerted by 2 kg block on 4 kg block will be

$F_n = -4 N$

5 0

3 years ago

A 1,450 kg car drives toward a 60 kg shopping cart that has a velocity of -1.2 m/s toward the car. The two objects collide, givi

Y_Kistochka [10]

Answer:

A) v₁ = 5.66 [m/s]

Explanation:

To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conservation before and after a collision.

The linear momentum is equal to the mass by the product of the Velocity.

P = m*v

where:

P = lineal momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

Now, to the right side of the equal sign will take the linear momentum before the collision and to the left side of the equal sign as after the collision.

Pbefore = Pafter

(m₁*v₁) - (m₂*v₂) = (m₁*v₃) + (m₂*v₄)

where:

m₁ = mass of the car = 1450 [kg]

v₁ = velocity of the car before the collision [m/s]

m₂ = mass of the shopping cart = 60 [kg]

v₂ = velocity of the shopping cart before the collision = -1.2 [m/s]

v₃ = velocity of the car after the collision = 5.13 [m/s]

v₄ = velocity of the shopping cart after the collision = 11.75 [m/s]

Now replacing:

(1450*v₁) - (60*1.2) = (1450*5.13) + (60*11.75)

1450*v₁ - 72 = 7438.5 + 705

1450*v₁ = 7438.5 + 705 + 72

1450*v₁ = 8215.5

v₁ = 5.66 [m/s]

4 0

3 years ago

Read 2 more answers

34000×0.4 ---------------- 0.02×200 In scientific notation

VashaNatasha [74]

Answer:

the simplified expression is written as 3.4 x 10³

Explanation:

Given expression;

$\frac{34000\times 0.4}{0.02 \times 200}$

in scientific notation, the expression is simplified as;

$\frac{34000\times 0.4}{0.02 \times 200} = \frac{13600}{4} = 3400 = 3.4 \times 10^3$

Therefore, in scientific notation, the simplified expression is written as 3.4 x 10³

4 0

3 years ago

The efforts of one good worker can often motivate others to reach their potential through a process called A. Modeling B. Mentor

olganol [36]

It would be A. Modeling.

4 0

3 years ago

Read 2 more answers