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avanturin [10]
2 years ago
15

An object is being shot from a horizontal ground at an incline angle of 30 degree with respect to the ground at a speed of 52 m/

s. Find the duration in seconds that the object is above the height of 14 m. Give your answer with one decimal place.
Physics
1 answer:
Alex2 years ago
8 0

When an object is thrown at an angle from the horizontal, the path followed by the body is called the projectile motion. The duration in seconds that the object is above the height of 14 m is 4.698 s.

<h3>What is speed?</h3>

Speed is the time rate at which velocity is changing.

Vertical speed component is

V₀y = 52sin 30°= 26 m/s

Given is the height h=14m

Using second equation of motion,

S=ut+ 1/2 at²

Substituting the values, we get

14 = 26t - 4.9t²

4.9t² - 26t +14 =0  

Solving the quadratic equation, we get the time as

taking the positive sign, t =4.698 s

taking the negative sign , t = 0.6082 s

Thus, the duration in seconds that the object is above the height of 14 m is 4.698s.

Learn more about speed.

brainly.com/question/7359669

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A shopping cart is given an initial velocity of 4 m/s and experiences a constant acceleration of 4 m/s2. What is the magnitude o
NNADVOKAT [17]

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48m

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From Second equation of motion ,

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Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air resistance.) With what initial velo
alukav5142 [94]

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Explanation:

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Since <em>at maximum height the speed will be v_f=0m/s</em>, the formula can be written as v_i=\sqrt{-2ad}, which for our values is:

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