Explanation:
Suppose the cheetah is initially positioned at x=0 (m) from the reference, and the gazelle is intially at poisiton x=d (m).
Then, at the worst case, that is when cheetah is running at the maximum case, the position of the gazelle relative to the reference must be larger than that of cheetah.
In equation form,
Answer:
When the pressure and the temperature are increased the volume is 285.7 ml.
Explanation:
We can find the new volume by using the Ideal Gas Law:
Where:
P: is the pressure
V: is the volume
n: is the number of moles
R: is the gas constant
T: is the temperature
Initially, when V₁ = 200 ml, P₁ = 500 torr and T₁ = 10 °C, we have:
(1)
And finally, when P₂ = 700 torr and T₂ = 20 °C, we have:
(2)
By equating (1) with (2):
Therefore, when the pressure and the temperature are increased the volume is 285.7 ml.
I hope it helps you!