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Mars2501 [29]
3 years ago
5

Two charges q1 and q2 exert a 90 N electrostatic force onto each other when they are 1 m apart. They are moved further away to a

distance of 3 m. What will the new electrostatic force be?
30 N
810 N
10 N
270 N
What is the gravitational force between two billiard balls of mass 156 g and 170 g that are 75 cm apart?
-2.36 x 10-12 N
2.36 x 10-12 N
3.15 x 10-12 N
-3.15 x 10-12 N
Based on Coulomb's law, which quantities does the acceleration of a charged particle due to the Coulomb force depend on?
The acceleration depends on the charge but not on the mass.
The acceleration does not depend on the charge nor on the mass.
The acceleration depends on the mass but not on the charge.
The acceleration depends on both the charge and the mass.
Two masses m1 and m2 exert a gravitational force of 20 N onto each other when they are 4 m apart.
At what distance should they be to exert a force of 5 N onto each other?
64 m
16 m
8 m
1 m
Physics
2 answers:
Dovator [93]3 years ago
6 0

Answer:

?????????????????????????

Blizzard [7]3 years ago
6 0

Answer:

If anyone is from connections someone shld make a quizlet w quick check answers

Explanation:

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borishaifa [10]
A polar molecules have charges that are free to move around
6 0
4 years ago
Please answer this question
nata0808 [166]

Answer:

Its sure 2nd gare beaciuse

Explanation:

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5 0
3 years ago
Can you help with this question please
Iteru [2.4K]

Answer:

First answer to the first question is Two people pulling a rope with the same force in a opposite direction.  The other one would be 2.72N        

Explanation:

Hope this helps you :)

7 0
3 years ago
A 2100 kg car starts from rest and accelerates at a rate of 2.6 m/s2 for 4.0 s. Assume that the force acting to accelerate the c
Reika [66]
When the system is experiencing a uniformly accelerated motion, there are a set of equations to work from. In this case, work is energy which consist solely of kinetic energy. That is, 1/2*m*v2. First, let's find the final velocity.

a = (vf - v0)/t
2.6 = (vf - 0)/4
vf = 10.4 m/s

Then W = 1/2*(2100 kg)*(10.4 m/s)2
W = 113568 J = 113.57 kJ
8 0
3 years ago
A stone is thrown vertically upward at a speed of 41.50 m/s at time t=0. A second stone is thrown upward with the same speed 3.0
lubasha [3.4K]

Answer:

t1 = t2 + 3.02         V = 41.5

V t1 - 1/2 g t1^2 = V t2 - 1/2 g t2^2

Both stones reach the same height after the specified times

V (t1 - t2) = g/2 (t1^2 - t2^2) = g/2 (t1 - t2) (t1 + t2)

2 V / g = t1 + t2 = 2t1 + 3.02

t1 = V / g - 1.51 = 41.5 / 9.8 -1.51 = 2.72 s

t2 = t1 + 3.02 = 5.74 sec

Check:

41.5 * 2.72 - 4.9 * 2.72^2 = 76.6 m

41.5 * 5.74 - 4.9 * 5.74^2 = 76.8 m

Speed of second stone = 41.5 - 9.8 * 2.72 = 14.8 m/s

7 0
3 years ago
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