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Oksi-84 [34.3K]
1 year ago
6

Circle the letter that corresponds to the best answer.

Physics
1 answer:
IrinaK [193]1 year ago
6 0

Answer:

C) China, or "Our largest trade deficit is with China"

Explanation:

China is currently our largest goods trading partner. 85% of goods are imported from China to America. The most prominent goods among the finished products exported from China were consumer electronics, data processing technologies, clothing, other textiles, optical gear, and medical equipment.

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What is the difference between deviation and incidence
yKpoI14uk [10]

Explanation:

<u><em>Deviation</em><em> </em><em>:</em><em> </em></u><em> </em>

It means the difference between a expected value of a measurement or an observation vs the actual value.

<em><u>Incidence</u></em><em><u> </u></em><em><u>:</u></em>

A straight line, ray of light, etc.., hits a surface at a point.

3 0
2 years ago
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You have a chart that illustrates a series of species with their common ancestor. This chart is a
emmasim [6.3K]
The answer is *C. Cladogram*.
8 0
3 years ago
A student drops a rubber ball onto a surface. Assume that this is a closed system. The ball bounces, but each successive bounce
spayn [35]
I would say D.) The ball bounces many times suggesting the energy is used up efficiently
5 0
2 years ago
Read 2 more answers
A box is being moved with a velocity (v) by a force P (parallel to v) along a level horizontal floor. The normal force is (Fn),
labwork [276]

Answer:

Force (P) : Positive

Normal Force (Fn) : Zero

Weight (mg) : Zero

Kinetic Frictional Force (fk) : Negative

Explanation:

The work done by a force on an object is given by the following formula:

W = F.d

W = F d Cosθ

where,

W = Work Done

f = Force Applied

d = displacement

θ = Angle between force and displacement

<u>FOR FORCE (P)</u>:

Since, force P is parallel to the motion of the box. Therefore, θ = 0°

Hence,

W = P d Cos 0°

W = P d(1)

W = Pd

<u>Therefore, work done by force (P) is Positive.</u>

<u></u>

<u>FOR NORMAL FORCE (Fn) AND WEIGHT (W)</u>:

Since, normal force and weight are perpendicular to the motion of the box. Therefore, θ = 90°

Hence,

W = Fn d Cos 90°= mg d Cos 90°

W = Fn d(0) = mg d (0)

W = 0

<u>Therefore, work done by Normal Force (Fn) and Weight (mg) is Zero.</u>

<u></u>

<u>FOR KINETIC FRICTIONAL FORCE (fk)</u>:

Since, kinetic frictional force acts in the opposite direction of motion of the box. Therefore, θ = 180°

Hence,

W = fk d Cos 180°

W = fk d(-1)

W = -fk d

<u>Therefore, work done by Kinetic Frictional Force (fk) is Negative.</u>

<u></u>

8 0
3 years ago
A student pushes a 2.85 kg cart causing it to accelerate at a rate of 4.9 m/s squared .What amount of force must the student hav
uysha [10]
In order to find the force (F), you would have to use the formula for it:
F=ma
where m is mass and a is acceleration.
In the problem, the mass is 2.85kg and the acceleration is 4.9m/s^2.
Therefore,
F=2.85kg(4.9m/s^2)
F=13.965kg(m/s^2)
Since N=kg(m/s^2)
F=13.965N
And because the problem requires that we use only 2 significant figures,
F=13N
Therefore, the student must exert 13N of force.

7 0
3 years ago
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