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3 years ago

Pushing a chair is a law of______?

Physics

2 answers:

Valentin [98]3 years ago

8 0

I believe your answer would be A. Due to the friction of pushing the chair while it’s on the floor

wlad13 [49]3 years ago

7 0

Answer:

A.Law of friction

Explanation:

because friction is the move chair floor

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3. Elements are organized on the<br><br> according to their

Oliga [24]

I don’t know if I’m completely right but Elements are arranged from left to right due to their atomic number

8 0

4 years ago

A road perpendicular to a highway leads to a farmhouse located 7 mile away. An automobile traveling on the highway passes throug

Fantom [35]

Answer:

The rate at which the automobile is moving away from the farmhouse is 27.29 m/h.

Explanation:

As shown in the figure, A denotes the position of farmhouse, B be the location of highway intersection and C be the direction along which automobile is moving.

Consider s be the distance between farmhouse and automobile which is represent by AC, x is the distance between intersection and automobile which is represent by BC and the distance between intersection of highway and automobile is represent by AB.

Applying Pythagoras Theorem to the figure,

(AB)² + (BC)² = (AC)²

Since, AB = 7 miles, BC = x and AC = s.

7² + x² = s²

Differentiating both sides of the above equation with respect to time :

$\frac{d}{dt}(7^{2} +x^{2} )=\frac{d}{dt}s^{2}$

$2x\frac{dx}{dt} = 2s\frac{ds}{dt}$

$\frac{x}{s}\frac{dx}{dt}=\frac{ds}{dt}$

$\frac{x}{\sqrt{7^{2}+x^{2} } }\frac{dx}{dt}=\frac{ds}{dt}$

When the automobile is 4 miles past the intersection, i.e.

x = 4 miles and $\frac{dx}{dt}$ = 55 m/h, then

$\frac{4}{\sqrt{7^{2}+4^{2} } }55=\frac{ds}{dt}$

$\frac{ds}{dt}=27.29$ m/h

3 0

3 years ago

A 1000 Kg car approaches an intersection traveling north at 30 m/s . A 1250 Kg car approaches the same intersection traveling ea

Feliz [49]

Answer:

The final velocity has a magnitude of 25.44 m/s and is at 31.61° north of east.

Explanation:

Taking north direction as positive y axis and east direction as positive x axis .

Given:

Mass of first car is, $m_1=1000\ kg$

Initial velocity of first car is, $u_1=30\vec{j}\ m/s$

Mass of second car is, $m_2=1250\ kg$

Initial velocity of second car is,

Let the combined final velocity after collision be 'v' m/s with as components of final velocity along east and north directions respectively.

Now, as the net external force is zero, momentum is conserved for the two car system along the east and north directions.

Conserving momentum along the east direction, we have:

Initial momentum = Final momentum

$m_1u_{1x}+m_2u_{2x}=(m_1+m_2)v_x\\\\0+1250\times 39=(1000+1250)v_x\\\\v_x=\frac{48750}{2250}\\\\v_x=\frac{65}{3} m/s$

There is no component of initial velocity for first car in east direction, as it is moving in the north direction. So,

Now, conserving momentum along the north direction, we have:

Initial momentum = Final momentum

$m_1u_{1y}+m_2u_{2y}=(m_1+m_2)v_y\\\\1000\times 30+0=(1000+1250)v_y\\\\v_y=\frac{30000}{2250}\\\\v_y=\frac{40}{3}\ m/s$

There is no component of initial velocity for second car in north direction, as it is moving in the east direction. So, $u_{2y}=0$ .

The magnitude of final velocity is given as:

$|\vec{v}|=\sqrt{(v_x)^2+(v_y)^2}\\\\|\vec{v}|=\sqrt{(\frac{65}{3})^2+(\frac{40}{3})^2}\\\\|\vec{v}|=\sqrt{\frac{5825}{9}}=25.44\ m/s$

The direction is given as:

$\theta=\tan^{-1}(\frac{v_y}{v_x})\\\\\theta=\tan^{-1}(\frac{\frac{40}{3}}{\frac{65}{3}})=31.61^\circ$

So, the final velocity has a magnitude of 25.44 m/s and is at 31.61° north of east.

7 0

3 years ago

What is the purpose of draeing a free-body diagrams

maria [59]

In order to see what forces are acting upon an object in every direction.

3 0

3 years ago

8. A crate of bananas weighing 3000 N is shipped from South America to New York, where it

LiRa [457]

Answer:

Mechanical advantage = 15

Explanation:

Given the following data;

Output force = 3000N

Input force = 200N

To find the mechanical advantage;

Mechanical advantage = output force/input force

Substituting into the equation, we have

Mechanical advantage = 3000/200

Mechanical advantage = 15

3 0

3 years ago