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bixtya [17]
3 years ago
9

Pushing a chair is a law of______?

Physics
2 answers:
Valentin [98]3 years ago
8 0
I believe your answer would be A. Due to the friction of pushing the chair while it’s on the floor
wlad13 [49]3 years ago
7 0

Answer:

A.Law of friction

Explanation:

because friction is the move chair floor

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Que es la friccion <br> Cual es la primera ley de newton
lidiya [134]

Answer:

huh?...................

5 0
3 years ago
A projectile is launched into the air with the initial speed of vi = 40 m/s at a launch angle of 20 degrees above the horizontal
Sphinxa [80]

The range of the projectile is 188 m

Explanation:

The motion of the arrow in this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction  

The path of a projectile is the combination of these two motions: see figure in attachment.

In order to find the horizontal range of the projectile, we just need to calculate the horizontal distance travelled.

We have:

t = 5.0 s (time of fligth of the projectile)

and the horizontal velocity is constant, and it is given by

v_x = v_i cos \theta

where

v_i = 40 m/s is the initial velocity

\theta=20^{\circ} is the angle of projection

Substituting,

v_x = (40)(cos 20^{\circ})=37.6 m/s

And therefore, the range of the projectile is:

d=v_x t = (37.6)(5.0)=188 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

5 0
3 years ago
Which situation will change the direction of the bicycle?
Elodia [21]

Answer:

Dont know if this is right but i say C

Explanation:

6 0
3 years ago
Whats a streams discharge?
KiRa [710]
 The <span>stream's discharge 
The volume of water to pass a given point on a stream bank per unit of time, usually expressed in cubic meters of water per second. </span>
5 0
3 years ago
A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is immersed in a uniform electr
Katen [24]

Answer:

ФE = 9.403W

Explanation:

In order to calculate the magnitude of the electric flux trough the sheet, you use the following formula:

\Phi_E=\vec{A}\cdot \vec{E}=AEcos\theta       (1)

A: area of the rectangular sheet = (0.400m)(0.600m) = 0.24m^2

E: magnitude of the electric field = 95.0N/C

θ: angle between the direction of the electric field and the normal to the surface of the sheet

You replace the values of the parameters in the equation (1):

\Phi_E=(0.24m^2)(95.0N/m)cos(20\°)=9.304W

The magnitude of the electric flux is trough the sheet is 9.403W

5 0
2 years ago
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